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pogonyaev
3 years ago
6

Connie flew from Phoenix to flagstaff, a distance of 180 miles at a constant speed of 180 miles per hour. She then returned to t

he same airport at a cj stand speed of 90. Miles per hour. What was connies average speed in miles/ hour
Physics
1 answer:
julsineya [31]3 years ago
5 0

Answer:

Average Velocity = 120 mi/h

Explanation:

First we need to calculate the time taken by Connie to complete first half from Phoenix to flagstaff. So, we use:

s₁ = v₁t₁

where,

s₁ = distance from Phoenix to flagstaff = 180 miles

v₁ = speed of travel from Phoenix to flagstaff = 180 mi/h

t₁ = time taken to travel from Phoenix to flagstaff = ?

Therefore,

180 miles = (180 m/h)t₁

t₁ = 1 h

Now, we calculate the time for the return trip

s₂ = v₂t₂

where,

s₂ = distance from flagstaff to Phoenix = 180 miles

v₂ = speed of travel from flagstaff to Phoenix = 90 mi/h

t₂ = time taken to travel from flagstaff to Phoenix = ?

Therefore,

180 miles = (90 m/h)t₂

t₂ = 2 h

Now, we find total time:

t = t₁ + t₂

t = 1 h + 2 h

t = 3 h

and the total distance was:

s = s₁ +s₂

s = 180 mi + 180 mi

s = 360 mi

So, the average velocity will be:

Average Velocity = s/t

Average Velocity = 360 mi/3 h

<u>Average Velocity = 120 mi/h</u>

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Explanation:

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x = 2.775 m

Rounded to 3 sig-figs, the astronaut halloweener reaches a maximum height of 2.78 meters.

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Answer:

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Explanation:

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D = m/v .............................. Equation 1.

Where D = Density of the solid copper sphere, m = mass of the solid copper sphere, v = volume of the solid copper sphere.

Making v the subject of the equation,

v = m/D............................... Equation 2

Given: m = 76.5 kg,

Constant: D = 8960 kg/m .

Substituting into equation 2

v = 76.5/8960

v = 0.0085379 m³

Since the copper sphere is to be drawn into wire,

Volume of the copper sphere = volume of the wire

v = volume of the wire

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Note: A wire takes the shape of a cylinder.

v = πd²L/4 ........................ equation 3.

making L the subject of the equation,

L = 4v/πd²..................... Equation 4

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Substitute into equation 4

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3 years ago
A 40.0 kg wagon is towed up a hill inclined at 18.5 degrees with respect to the horizontal. The tow rope is parallel to the incl
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Answer:

7.9m/s

Explanation:

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\theta=18.5^{\circ}

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Initial velocity of wagon=u=0

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Net force applied  on wagon=F=T-mgsin\theta=140-40(9.8)sin18.5=15.7 N

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