Answer:
For any collision occurring in an isolated system, momentum is conserved. The total amount of momentum of the collection of objects in the system is the same before the collision as after the collision.
Explanation:
Hope this helps
Answer: 5billion years
Explanation: The sun produces energy through radioactive fusion reaction.
Nebula theory states that the gaseous particles of the Earth collapsed as a result of its own gravity which continuously lead to fusion reaction for the production of nuclear energy.
The Core of the Sun is that area up to 25% from the radius of the sun,here the pressure here range up to 250million atmosphere containing mainly hydrogen which gets converted in Helium molecule. The core is the center for energy production accounting for more than 98%, nuclear energy is transmitted at about 4.3million metric tons per second.
Answer:
51793 bright-dark-bright fringe shifts are observed when the mirror M2 moves through 1.7cm
Explanation:
The number of maxima appearing when the mirror M moves through distance \Delta L is given as follows,
![\Delta m = \frac{\Delta L}{\frac{\lambda}{2}}](https://tex.z-dn.net/?f=%5CDelta%20m%20%3D%20%5Cfrac%7B%5CDelta%20L%7D%7B%5Cfrac%7B%5Clambda%7D%7B2%7D%7D)
Here,
= is the distance moved by the mirror M
is the wavelenght of the light used.
= 0.017m
![\lambda = 656.45*10^{-9}m](https://tex.z-dn.net/?f=%5Clambda%20%3D%20656.45%2A10%5E%7B-9%7Dm)
![\Delta m = \frac{0.017}{\frac{656.45*10^{-9}}{2}}](https://tex.z-dn.net/?f=%5CDelta%20m%20%3D%20%5Cfrac%7B0.017%7D%7B%5Cfrac%7B656.45%2A10%5E%7B-9%7D%7D%7B2%7D%7D)
![\Delta m = 51793.72](https://tex.z-dn.net/?f=%5CDelta%20m%20%3D%2051793.72)
Therefore, 51793 bright-dark-bright fringe shifts are observed when the mirror M2 moves through 1.7
Answer:
2d
Explanation:
For any instance equivalent force acting on the body is
![mg-kd= m\frac{d}{dt}\frac{dx}{dt}](https://tex.z-dn.net/?f=mg-kd%3D%20m%5Cfrac%7Bd%7D%7Bdt%7D%5Cfrac%7Bdx%7D%7Bdt%7D)
Where
m is the mass of the object
k is the force constant of the spring
d is the extension in the spring
and
d/dt(dx/dt)= is the acceleration of the object
solving the above equation we get
![x= Asin\omega t +d](https://tex.z-dn.net/?f=x%3D%20Asin%5Comega%20t%20%2Bd)
where
![\omega= \sqrt{\frac{k}{m} } = \frac{2\pi}{T}](https://tex.z-dn.net/?f=%5Comega%3D%20%5Csqrt%7B%5Cfrac%7Bk%7D%7Bm%7D%20%7D%20%3D%20%5Cfrac%7B2%5Cpi%7D%7BT%7D)
A is the amplitude of oscillation from the mean position.
k= spring constant , T= time period
Here we are assuming that at t=T/4
x= 0 since, no extension in the spring
then
A=- d
Hence
x=- d sin wt + d
now, x is maximum when sin wt=- 1
Therefore,
x(maximum)=2d