Answer:
a. They are staying at the same speed
Explanation:
IF CORRECT PLSPLSPLS GIVE BRAINLIEST WOULD APPRECIATE :)
Answer:
No. of molecules= mass/molar mass ×avogadro no.
= 13.2/50×6.02×10°23
No. of molecules =1.59×10°23
Explanation:
Answer:
Depression in freezing point = 2 X 1.853 X 0.25 = 0.9625
Thus this will be the difference between the freezing point of pure water and the solution.
Explanation:
On adding any non volatile solute to a solvent its boiling point increases and its freezing point decreases [these are two of the four colligative properties].
The depression in freezing point is related to molality of solution as:
ΔTf
where
ΔTf= depression in freezing point
Kf= cryoscopic constant of water = 1.853 K. kg/mol.
i = Van't Hoff factor = 2 ( for KCl)
molality = 
moles of solute = mass / molarmass = 4.66 / 74.55 =0.0625
mass of solvent = mass of solution (almost)
considering the density of solution to be 1g/mL
mass of solvent = 250 grams = 0.250 Kg
molality = 
Putting values
depression in freezing point = 2 X 1.853 X 0.25 = 0.9625
Thus this will be the difference between the freezing point of pure water and the solution.
The catalyst would increase the rate of the forward reaction...
And increase the rate of the backward to the same extent thus not affecting equilibrium.