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dlinn [17]
3 years ago
7

Lab Report

Chemistry
1 answer:
Alenkasestr [34]3 years ago
4 0

Answer:

I know some of them...

Explanation:

1. What was the purpose of the experiment?

Type your answer here: The purpose of this experiment is to show that a cell membrane is a type of barrier, and is permeable to some substances, but may not be permeable to all substances.

2. What were the independent, dependent, and control variables in your investigation? Describe the variables used in the part of the experiment with the eggs.

Type your answer here: Independent variable / Manipulated variable: Refers to all the variables in an experiment that provoke a response in another variable. This variable is modified during the experiment to analyze how another variable responds to it. The researcher wants to study how the changes in these variables affect the dependent variable.  The researcher can change these variables to see what changes it implies in an object, process, trait, or anything that depends on them.

Dependent variable / Responding variable: Its response depends on any change in the independent variable. The dependent variable is the one that is being investigated, studied, and measured. It represents a quantity of something which value depends on how the independent variable is modified. It is usually identified by the letter Y.  A change in the dependent variable might be proportional or inversely proportional to the change in the manipulated variable. In the exposed example, the dependent variable is the egg circumference.

Constants / Controlled variables: Refers to those variables in an experiment that are controlled and have no influence on the results. These variables do not affect the change in the dependent variable values. In the exposed example the use of the lid to seal the jar and the amount and concentration of vinegar might be considered as a controlled variable. These elements are used but do not provoke any change in the size of the egg.

thats it... CAN SOMEONE ANSWER THE OTHERS?! I NEED ITT

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If a student mixes 75 mL of 1.30 M HNO3 and 150 mL of 6.5 M NaOH. is the final solution acidic, basic, or neutral
raketka [301]

Answer:

The solution is basic.

Explanation:

We can determine the nature of the solution via determining which has the large no. of millimoles (acid or base):

  • If no. of millimoles of acid > that of base; the solution is acidic.
  • If no. of millimoles of acid = that of base; the solution is neutral.
  • If no. of millimoles of acid < that of base; the solution is basic.

  • We need to calculate the no. of millimoles of acid and base:

no. of millimoles of acid (HNO₃) = MV = (1.3 M)(75.0 mL) = 97.5 mmol.

no. of millimoles of base (NaOH) = MV = (6.5 M)(150.0 mL) = 975.0 mmol.

<em>∴ The no. of millimoles of base (NaOH) is larger by 10 times than the acid (HNO₃).</em>

<em>So, the solution is: basic.</em>

4 0
3 years ago
What mass of H₂ is needed to react with 8.75 g of O₂ according to the following equation: O2(g) + H2(g) → H₂O(g)?
FromTheMoon [43]

Explanation:

For reacting with 8.75 grams of oxygen, 1.08 grams of hydrogen is required.

The given balanced equation has been:

\rm O_2\;+\;2\;H_2\;\rightarrow\;H_2OO2+2H2→H2O

From the equation, 1 mole of oxygen reacts with 2 mole of hydrogen to give 1 mole of water.

The mass of oxygen has been: 8.75 g,

Moles = \rm \dfrac{weight}{molecular\;weight}molecularweightweight

Moles of oxygen = \rm \dfrac{8.75}{32}328.75

Moles of oxygen = 0.27 mol

Since,

1 mole Oxygen = 2 mole hydrogen

0.21 mol oxygen = 0.54 mol hydrogen

Mass of hydrogen = moles \times× molecular weight

Mass of hydrogen = 0.54 \times× 2

Mass of hydrogen = 1.08 grams.

Thus, for reacting with 8.75 grams of oxygen, 1.08 grams of hydrogen is required.

6 0
2 years ago
What is the least informative property of a mineral
Scrat [10]
All of them are important to identify a mineral and get information from it, but I'd say the least important is cleavage.
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When liquid silver nitrate and liquid sodium chloride are combined it becomes
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Answer:

solid silver chloride forms along with a new liquid, sodium nitrate

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