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s2008m [1.1K]
3 years ago
5

Mass is an intensive physical property because it is dependent on the size of the sample.

Chemistry
2 answers:
SVETLANKA909090 [29]3 years ago
4 0
Hi,
That’s FALSE. An intensive physical property is one that is independent of the size of the sample. Mass, on the other hand, is an extensive physical property, because it is dependent on the size of the sample.

Ann [662]3 years ago
4 0

Answer:

False

Explanation:

Physical properties of matter can be broadly classified into two categories:

-Intensive property

-Extensive property

Intensive properties are independent of the size or mass of matter i.e. they do not change as 'quantity' of matter changes. This includes: density, temperature, pressure etc

Extensive properties, in contrast are mass dependent and change as the amount of matter changes. Some examples include: mass, volume etc

The statement that mass is an intensive physical property because it is dependent on the size of the sample is False, instead mass is an extensive property.

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Find the solubility of agi in 2.5 m nh3 [ksp of agi = 8.3 × 10−17; kf of ag(nh3)2+ = 1.7 × 107].
vovangra [49]
When the first reaction equation is:

AgI(S) ↔ Ag+(Aq)  +  I-(Aq)

So, the Ksp expression = [Ag+][I-]

∴Ksp = [Ag+][I-] = 8.3 x 10^-17

Then the second reaction equation is:

 Ag+(aq)  + 2NH3(aq) ↔  Ag(NH3)2+  

So, Kf expression = [Ag(NH3)2+] / [Ag+] [NH3]^2

∴Kf = [Ag(NH3)2+] /[Ag+] [NH3]^2 = 1.7 x 10^7

by combining the two equations and solve for Ag+:

and by using ICE table:

               AgI(aq) + 2NH3  ↔  Ag(NH3)2+  + I-
initial                        2.5                    0            0 

change                    -2X                    +X             +X

Equ                     (2.5-2X)                   X               X

so K = [Ag(NH3)2+] [I-] / [NH3]^2

Kf * Ksp = X^2 / (2.5-2X)

8.3 x 10^-17 * 1.7 x10^7 = X^2 / (2.5-2X) by solving for X

∴ X = 5.9 x 10^-5 

∴ the solubility of AgI = X = 5.9 x 10^-5 M

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3 years ago
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WHat's a concept map again?

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3 years ago
If a force of 1.4N is applied to a block with a mass of 7kg, what is the acceleration of the block in meters per second squared?
Anton [14]

Answer:

<h2>0.2 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{1.4}{7} =  \frac{1}{5}   \\

We have the final answer as

<h3>0.2 m/s²</h3>

Hope this helps you

5 0
3 years ago
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lys-0071 [83]
No need 4 calculatinh
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