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s2008m [1.1K]
3 years ago
5

Mass is an intensive physical property because it is dependent on the size of the sample.

Chemistry
2 answers:
SVETLANKA909090 [29]3 years ago
4 0
Hi,
That’s FALSE. An intensive physical property is one that is independent of the size of the sample. Mass, on the other hand, is an extensive physical property, because it is dependent on the size of the sample.

Ann [662]3 years ago
4 0

Answer:

False

Explanation:

Physical properties of matter can be broadly classified into two categories:

-Intensive property

-Extensive property

Intensive properties are independent of the size or mass of matter i.e. they do not change as 'quantity' of matter changes. This includes: density, temperature, pressure etc

Extensive properties, in contrast are mass dependent and change as the amount of matter changes. Some examples include: mass, volume etc

The statement that mass is an intensive physical property because it is dependent on the size of the sample is False, instead mass is an extensive property.

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Answer:

Z=22.70

Explanation:

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An element Z that has two naturally occurring isotopes with the following percent abundances as follows :

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The average atomic mass for element Z is given by :

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3 years ago
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A sample of an unknown metal has a mass of 58.932g. it has been heated to 101.00 degrees C, then dropped quickly into 45.20 mL o
yaroslaw [1]
<h3>Answer:</h3>

0.111 J/g°C

<h3>Explanation:</h3>

We are given;

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  • Initial temperature of the metal sample as 101°C
  • Final temperature of metal is 23.68 °C
  • Volume of pure water = 45.2 mL

But, density of pure water = 1 g/mL

  • Therefore; mass of pure water is 45.2 g
  • Initial temperature of water = 21°C
  • Final temperature of water is 23.68 °C
  • Specific heat capacity of water = 4.184 J/g°C

We are required to determine the specific heat of the metal;

<h3>Step 1: Calculate the amount of heat gained by pure water</h3>

Q = m × c × ΔT

For water, ΔT = 23.68 °C - 21° C

                       = 2.68 °C

Thus;

Q = 45.2 g × 4.184 J/g°C × 2.68°C

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<h3>Step 2: Heat released by the unknown metal sample</h3>

We know that, Q =  m × c × ΔT

For the unknown metal, ΔT = 101° C - 23.68 °C

                                              = 77.32°C

Assuming the specific heat capacity of the unknown metal is c

Then;

Q = 58.932 g × c × 77.32°C

   = 4556.62c Joules

<h3>Step 3: Calculate the specific heat capacity of the unknown metal sample</h3>
  • We know that, the heat released by the unknown metal sample is equal to the heat gained by the water.
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4556.62c Joules = 506.833 Joules

c = 506.833 ÷4556.62

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Thus, the specific heat capacity of the unknown metal is 0.111 J/g°C

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