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Brums [2.3K]
3 years ago
12

Using off-road vehicles does not contribute to the process of erosion. true or false

Chemistry
2 answers:
Artemon [7]3 years ago
7 0
Using off road vehicles does help contribute to the process of erosion.
Lera25 [3.4K]3 years ago
7 0

The answer is False.

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100 PTS+BRAINILIEST: Why does it get colder as you go higher through the atmosphere, if you are getting closer to the sun??
sattari [20]

Answer/Explanation:

Heat from the sun hits the ground and is absorbed. The higher you go, it gets more colder due to the fact that the air doesn't hold onto the radiation as it goes straight through the ground, which is why the top of mountains are very cold, and people are able to die in minutes.

8 0
2 years ago
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The halpy of vaporization of H2O at 1 atm and 100 C is 2259 kJ/kg. The heat capacity of liquid water is 4.19 kJ/kg.C, and the he
Naddik [55]

Answer: Option (a) is the correct answer.

Explanation:

The given data is as follows.

        C_{p}_{liquid} = 4.19 kJ/kg ^{o}C

        C_{p}_{vaporization} = 1.9 kJ/kg ^{o}C

Heat of vaporization (\DeltaH^{o}_{vap}) at 1 atm and 100^{o}C is 2259 kJ/kg

        H^{o}_{liquid} = 0

Therefore, calculate the enthalpy of water vapor at 1 atm and 100^{o}C as follows.

            H^{o}_{vap} = H^{o}_{liquid} + \DeltaH^{o}_{vap}        

                                   = 0 + 2259 kJ/kg

                                   = 2259 kJ/kg

As the desired temperature is given 179.9^{o}C and effect of pressure is not considered. Hence, enthalpy of liquid water at 10 bar and 179.9^{o}C is calculated as follows.

             H^{D}_{liq} = H^{o}_{liquid} + C_{p}_{liquid}(T_{D} - T_{o})

                             = 0 + 4.19 kJ/kg ^{o}C \times (179.9^{o}C - 100^{o}C)

                              = 334.781 kJ/kg

Hence, enthalpy of water vapor at 10 bar and 179.9^{o}C is calculated as follows.

               H^{D}_{vap} = H^{o}_{vap} + C_{p}_{vap} \times (T_{D} - T_{o})

             H^{D}_{vap} = 2259 kJ/kg + 1.9 \times (179.9 - 100)            

                              = 2410.81 kJ/kg

Therefore, calculate the latent heat of vaporization at 10 bar and 179.9^{o}C as follows.

       \Delta H^{D}_{vap} = H^{D}_{vap} - H^{D}_{liq}              

                         = 2410.81 kJ/kg - 334.781 kJ/kg

                         = 2076.029 kJ/kg

or,                      = 2076 kJ/kg

Thus, we can conclude that at 10 bar and 179.9^{o}C latent heat of vaporization is 2076 kJ/kg.

3 0
4 years ago
To enter or leave a cell substance must pass through
Rzqust [24]

The cell membrane. The cell membrane controls what will leave and enter the cell, not only that but it also helps support and protect the cell.
5 0
3 years ago
Give me types of acids
Alexxx [7]

pls follow me

Explanation:

The five common acids are sulfuric acid, hydrochloric acid, nitric acid, lactic acid, and acetic acid.

hope it helps:)

6 0
3 years ago
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What is the definition of atom
yuradex [85]

Answer:

An atom is the basic particle elements are made from

6 0
3 years ago
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