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ICE Princess25 [194]
3 years ago
9

What coefficients are needed to balance the equation for the complete combustion of methane? enter the coefficients in the order

ch4, o2, co2, and h2o, respectively.

Chemistry
2 answers:
Art [367]3 years ago
3 0

The coefficients in the order CH₄, O₂, CO₂, and H₂O, are 1,2,1,2

The equation becomes:

CH₄ (g) + 2O₂ (g) -> CO₂ (g) + 2H₂0 (g)

<h3><em>Further explanation</em></h3>

Complete combustion of hydrocarbon with oxygen will be obtained by CO₂ and H₂O compounds.

If O is insufficient there will be incomplete combustion produced by CO and H and O

Hydrocarbon combustion reactions (specifically alkanes)

\large {\boxed {\bold {C_nH _ (_2_n _ + _ 2_) + \frac {3n + 1} {2} O_2 ----> nCO_2 + (n + 1) H_2O}}}

Equalization of chemical reaction equations can be done using variables.

Steps in equalizing the reaction equation:

  • 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.
  • 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product
  • 3. Select the coefficient of the substance with the most complex chemical formula equal to 1

For gas combustion reaction which is a reaction of hydrocarbons with oxygen produces CO₂ and H₂O (water vapor). can use steps:

Balancing C atoms, H and last atoms O atoms

Methana combustion reaction

CH₄ (g) + O₂ (g) -> CO₂ (g) + H₂0 (g)

We give the most complex compounds, namely Methane, we give the number 1

So the reaction becomes

CH₄ (g) + aO₂ (g) -> bCO₂ (g) + cH₂0 (g)

C atom on the left 1, right b, so b = 1

H atom on the left 4, right 2c, so 2c = 4 ---> c = 2

Atom O on the left 2a, right 2b + c, so 2a = 2b + c

2a = 2.1 + 2

2a = 4

a = 2

The equation becomes:

CH₄ (g) + 2O₂ (g) -> CO₂ (g) + 2H₂0 (g)

<h3><em>Learn more</em></h3>

the combustion of octane in gasoline

brainly.com/question/8175791

brainly.com/question/897044

hydrogen and excess oxygen

brainly.com/question/1405182

Keywords: methane, combustion, hydrocarbons, equalization of reaction equations

4vir4ik [10]3 years ago
3 0

The balanced chemical equation is as follows:

{\text{C}}{{\text{H}}_4}\left( g \right) + 2{{\text{O}}_2}\left( g \right) \to {\text{C}}{{\text{O}}_{\text{2}}}\left( g \right) + 2{{\text{H}}_{\text{2}}}{\text{O}}\left( g \right)

The coefficients of {\mathbf{C}}{{\mathbf{H}}_{\mathbf{4}}} is \boxed1, {{\mathbf{O}}_{\mathbf{2}}} is \boxed2, {\mathbf{C}}{{\mathbf{O}}_{\mathbf{2}}} is \boxed1 and {{\mathbf{H}}_{\mathbf{2}}}{\mathbf{O}} is \boxed2

Further Explanation:

The chemical reaction that contains equal number of atoms of the different elements in the reactant as well as in the product side is known as balanced chemical reaction. The chemical equation is required to be balanced to follow the Law of the conservation of mass.

<em>Combustion reaction</em> is the reaction in which the reactant reacts with molecular oxygen to form <em>carbon dioxide</em> and <em>water molecule</em>. <em>Molecular</em> <em>oxygen</em> acts as the <em>oxidizing agent</em> in these reactions. The large amount of heat is released and therefore combustion reactions are <em>exothermic reaction. </em>

The steps to balance a chemical reaction are as follows:

Step 1: Complete the reaction and write the unbalanced symbol equation.

In the combustion reaction, {\text{C}}{{\text{H}}_4} reacts with {{\text{O}}_2} to form {\text{C}}{{\text{O}}_{\text{2}}} and {{\text{H}}_{\text{2}}}{\text{O}}. The physical state of {\text{C}}{{\text{H}}_4} is gas, {{\text{O}}_2} is gas, {\text{C}}{{\text{O}}_{\text{2}}} is gas and {{\text{H}}_{\text{2}}}{\text{O}} is gas. The unbalanced chemical equation is as follows:

{\text{C}}{{\text{H}}_4}\left(g\right)+{{\text{O}}_2}\left(g\right)\to{\text{C}}{{\text{O}}_{\text{2}}}\left(g\right)+{{\text{H}}_{\text{2}}}{\text{O}}\left(g\right)

Step 2: Then we write the number of atoms of all the different elements that are present in a chemical reaction in the reactant side and product side separately. There is one carbon atom on both the reactant and product side. 2 oxygen atoms are present on the reactant side while 3 oxygen atoms are present on the product side. The number of hydrogen atoms on the reactant and product sides is 4 and 2 respectively. (Refer table in the attached image).

Step 3: Initially, we try to balance the number of other atoms of elements except for carbon, oxygen, and hydrogen by multiplying with some number on any side but in the combustion reaction there is only carbon, hydrogen and oxygen atom.

Step 4: After this, we balance the number of atoms of oxygen and then carbon atom followed by hydrogen atoms. To balance the number of atoms of oxygen and hydrogen, we have to multiply {{\text{O}}_2} by 2 and {{\text{H}}_{\text{2}}}{\text{O}} by 2. The chemical equation is as follows:

{\text{C}}{{\text{H}}_4}\left(g\right)+2{{\text{O}}_2}\left(g\right)\to{\text{C}}{{\text{O}}_{\text{2}}}\left(g\right)+2{{\text{H}}_{\text{2}}}{\text{O}}\left(g\right)

Step 5: Finally, we check the number of atoms of each element on both sides. If the number is same then the chemical equation is balanced. The balanced chemical equation is as follows:

{\text{C}}{{\text{H}}_4}\left(g\right)+2{{\text{O}}_2}\left( g \right) \to{\text{C}}{{\text{O}}_{\text{2}}}\left(g\right)+2{{\text{H}}_{\text{2}}}{\text{O}}\left(g\right)

The coefficients of {\text{C}}{{\text{H}}_4} is 1,  {{\text{O}}_2} is 2, {\text{C}}{{\text{O}}_{\text{2}}} is 1 and {{\text{H}}_{\text{2}}}{\text{O}} is 2.

Learn more:

1. Balanced chemical equation brainly.com/question/1405182

2. Learn more about how to calculate moles of the base in given volume brainly.com/question/4283309

Answer details:  

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: Balancing, CH4, O2, CO2, H2O, phases, physical state, solid, liquid, gas, aqueous, coefficients, and combustion reactions.

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A chemical equation that does not indicate relative amounts of reactants and products is called
Zielflug [23.3K]

Answer:

The correct answer is skeleton equation.

Explanation:

In chemistry, the skeletal formula of a compound is an abbreviated representation of its molecular structure. Skeleton formulas are used because they clearly show complicated structures, they are fast and simple to draw.

All atoms that are not carbon or hydrogen are represented by their chemical symbol. The relative amounts of reagents and products are not indicated.

Have a nice day!

6 0
3 years ago
if you find that a substance turns litmus paper to blue and contains hydroxide ions what would it most lightly be
Delicious77 [7]
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5 0
3 years ago
the density of glycerin is 1.26 g/cm3. How many pounds/foot3 is this ? use the conversion rates of 454g/1 pound and 28,317cm3/1f
lyudmila [28]

Answer:

78.6 lb/ft³  

Step-by-step explanation:

Let's do this in steps.

1. Convert grams to pounds

D = (1.26 g/1 cm³) × (1 lb/454 g)

   = 2.775 × 10⁻³ lb/cm³

2. Convert cubic centimetres to cubic feet

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6 0
3 years ago
What term refers to the small parts of a cell that carry out different functions?
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4 0
3 years ago
Draw a lewis structure for ketene, c2h2o, which has a carbon–carbon double bond
MrMuchimi

Visual representation of covalent bonding indicating the valence shell electrons in the molecule, lines represents the shared pair of electron and pair of electrons that are not involved in bonding are represented as dots(lone pairs) are known as Lewis structures.

Compound formation takes place in order to complete the octet of each element that is according to octet rule, each atom forms bond with other atom in order to complete their octet that is to get eight electrons in its valence shell and attain stability.

An organic compound of the form R^{'}R^{''}C=C=O is known as ketene.

The given ketene is C_2H_2O.

The number of valence electron of:

C = 4

H = 1

O = 6

The number of valence electrons in C_2H_2O = 2\times 4+2\times 1+1\times 6 =16

2 electrons are involved in each single bond between carbon and hydrogen and 4 electrons are involved in each double bond formed between carbon-carbon and carbon-oxygen. Hence, the total number of electrons involved in bond formation are 12 and rest 2 pair of electrons are present on oxygen as lone pair of electrons.

Therefore, the attached image is the Lewis structure of C_2H_2O .

8 0
3 years ago
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