All categories

3 years ago

Can any one complete metric tic tac toe

Chemistry

2 answers:

Novay_Z [31]3 years ago

7 0

0|_|_ 0|_|_
_|0|_ 0|_|_
| |0 0| |

_|_|0 _|_|0
_|0|_ _|_|0
0| | | |0

dsp733 years ago

7 0

Answer:

Can someone help me with this?

Explanation:

You might be interested in

How many moles of hcl are required to neutralize aqueous solutions of these bases:

Lemur [1.5K]

The answers are a.) 0.03 mol KOH requires 0.03 mol HCl, b.) 2 mol NH3 requires 2 mol HCl and c.) 0.1 mol Ca(OH)2 requires 0.2 mol HCl.
Solution:
We need to write the balanced equations for each reactions to find out the stoichiometry for each reactants.
a.) HCl (aq) + KOH (aq) → KCl (aq) + H2O(ℓ)
From the balanced equations, we can see that 1 HCl reacts with 1 KOH, therefore if 0.03 mol KOH is reacted then 0.03 mol HCl must also be present.

b.) HCl(aq) + NH3(aq) ) → NH4Cl(aq)
If 2 moles of NH3 are reacted then 2 moles of HCl must also be present since 1 HCl reacts with 1 NH3 from the balanced reaction.

c.) 2HCl(aq) + Ca(OH)2(s) → CaCl2(aq) + 2H2O(ℓ)
We can see that 2 HCl react with 1 Ca(OH)2, hence if 0.1 mol of Ca(OH)2 is reacted then 0.2 mol HCl must also be present.

8 0

3 years ago

Read 2 more answers

is the general formula of a certain hydrate. When 256.3 g of the compound is heated to drive off the water, 214.2 g of anhydrous

Marizza181 [45]

Answer:

The general formula of the hydrate is Caa Seb Oc. nH2O. Based on the given information, the weight of the hydrated compound is 256.3 grams, the weight of the anhydrous compound is 214.2 grams.

Therefore, the weight of water evaporated is 256.3 g - 214.2 g = 42.1 grams

The molecular weight of water is 18 gram per mole. So, the number of moles of water will be,

Moles of water = weight of water/molecular weight

= 42.1 grams / 18 = 2.3

The given composition of calcium is 21.90 %. So, the concentration of calcium in anhydrous compound is,

= 214.2 * 0.2190 = 46.91 grams

The given composition of Se is 43.14 %. So, the concentration of selenium in anhydrous compound is,

= 214.2 * 0.4314 = 92.40 grams

The given composition of oxygen is 34.97%, So, the concentration of oxygen in anhydrous compound is,

= 214.2 * 0.3497 = 74.91 grams

The molecular weight of Ca is 40.078, the obtained concentration is 46.91 grams, stoichiometry will be, 46.91/40.078 = 1.17

The molecular weight of Se is 78.96, the obtained concentration is 92.40, stoichiometry will be,

92.40/78.96 = 1.17

The molecular weight of Oxygen is 15.999, the concentration obtained is 74.91, the stoichiometry will be,

74.91/15.999 = 4.68.

Thus, the formula becomes, Ca1.17. Se1.1e O4.68. 2.3H2O, the closest actual component is CaSeO4.2H2O

6 0

4 years ago

5.Apply six atoms of Element A combined with eight atoms of Element B

Julli [10]

Answer:24

Explanation:axtizent

4 0

3 years ago

Which of the following is true about an ionic compound?

Genrish500 [490]

<span>D. all of the above because ionic compound is a salt. it is also held together by ionic bonds. it has anions and cations </span>

3 0

3 years ago

Read 2 more answers

The amount of protein in a sample was measured by the sample's absorbance of light at a given wavelength. Using standards, a bes

FinnZ [79.3K]

Answer:

Protein Concentration is 2.82mg/L

Explanation:

According to Beer-Lambert's Law, Absorbance is directly proportional to the concentration.

However, the concentration of a solution can be determined from a calibration curve, in which Absorbance is plotted on the y-axis and the Concentration on the x-axis.

Plotting the best line, the equation of line is used

y = mx + c

where y is absorbance = 0.150

m is slope = 0.0163

x is concentration

c is intercept = 0.104

inserting the values from the question

y = mx + c

0.150 = 0.0163x + 0.104

0.0163x = 0.150 - 0.104

0.0163x = 0.046

Divide both sides by 0.0163

0.0163x/0.0163 = 0.046/0.0163

x = 2.82

Concentration of protein = 2.82 mg/L

5 0

3 years ago