Answer:
<h2>D. 3</h2>
Step-by-step explanation:
![\bold{METHOD\ 1}](https://tex.z-dn.net/?f=%5Cbold%7BMETHOD%5C%201%7D)
![\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{x-intercept:}\ (x,\ 0).\\\\\text{Susbtitute the coordinates of the points to the formula of a slope}\\\\(-3,\ -4),\ (6,\ 2),\ (x,\ 0):\\\\m=\dfrac{2-(-4)}{6-(-3)}=\dfrac{2+4}{6+3}=\dfrac{6}{9}=\dfrac{6:3}{9:3}=\dfrac{2}{3}\\\\m=\dfrac{0-2}{x-6}=\dfrac{-2}{x-6}\\\\\text{Therefore we have the equation:}\\\\\dfrac{-2}{x-6}=\dfrac{2}{3}\qquad\text{cross multiply}\\\\2(x-6)=(-2)(3)\\\\2(x-6)=-6\qquad\text{divide both sides by 2}\\\\x-6=-3\qquad\text{add 6 to both sides}\\\\x=3](https://tex.z-dn.net/?f=%5Ctext%7BThe%20formula%20of%20a%20slope%3A%7D%5C%5C%5C%5Cm%3D%5Cdfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%5C%5C%5C%5C%5Ctext%7Bx-intercept%3A%7D%5C%20%28x%2C%5C%200%29.%5C%5C%5C%5C%5Ctext%7BSusbtitute%20the%20coordinates%20of%20the%20points%20to%20the%20formula%20of%20a%20slope%7D%5C%5C%5C%5C%28-3%2C%5C%20-4%29%2C%5C%20%286%2C%5C%202%29%2C%5C%20%28x%2C%5C%200%29%3A%5C%5C%5C%5Cm%3D%5Cdfrac%7B2-%28-4%29%7D%7B6-%28-3%29%7D%3D%5Cdfrac%7B2%2B4%7D%7B6%2B3%7D%3D%5Cdfrac%7B6%7D%7B9%7D%3D%5Cdfrac%7B6%3A3%7D%7B9%3A3%7D%3D%5Cdfrac%7B2%7D%7B3%7D%5C%5C%5C%5Cm%3D%5Cdfrac%7B0-2%7D%7Bx-6%7D%3D%5Cdfrac%7B-2%7D%7Bx-6%7D%5C%5C%5C%5C%5Ctext%7BTherefore%20we%20have%20the%20equation%3A%7D%5C%5C%5C%5C%5Cdfrac%7B-2%7D%7Bx-6%7D%3D%5Cdfrac%7B2%7D%7B3%7D%5Cqquad%5Ctext%7Bcross%20multiply%7D%5C%5C%5C%5C2%28x-6%29%3D%28-2%29%283%29%5C%5C%5C%5C2%28x-6%29%3D-6%5Cqquad%5Ctext%7Bdivide%20both%20sides%20by%202%7D%5C%5C%5C%5Cx-6%3D-3%5Cqquad%5Ctext%7Badd%206%20to%20both%20sides%7D%5C%5C%5C%5Cx%3D3)
![\bold{METHOD\ 2}\\\\\text{Look at the picture.}](https://tex.z-dn.net/?f=%5Cbold%7BMETHOD%5C%202%7D%5C%5C%5C%5C%5Ctext%7BLook%20at%20the%20picture.%7D)
Mark points in the coordinate system.
Lead a line through these points.
Read x-intercept.
One way would be to find the distance from the point to the center of the circle and compare it to the radius
for
![(x-h)^2+(y-k)^2=r^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3Dr%5E2)
the center is (h,k) and the radius is r
and the distance formula is
distance between
![(x_1,y_1)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29)
and
![(x_2,y_2)](https://tex.z-dn.net/?f=%28x_2%2Cy_2%29)
is
![D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%28x_1-x_2%29%5E2%2B%28y_1-y_2%29%5E2%7D)
r=radius
D=distance form (8,4) to center
if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle
so
![(x+2)^2+(y-3)^2=18](https://tex.z-dn.net/?f=%28x%2B2%29%5E2%2B%28y-3%29%5E2%3D18)
![(x-(-2))^2+(y-3)^2=(\sqrt{18})^2](https://tex.z-dn.net/?f=%28x-%28-2%29%29%5E2%2B%28y-3%29%5E2%3D%28%5Csqrt%7B18%7D%29%5E2)
![(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2](https://tex.z-dn.net/?f=%28x-%28-2%29%29%5E2%2B%28y-3%29%5E2%3D%283%5Csqrt%7B2%7D%29%5E2)
the radius is
![3\sqrt{2}](https://tex.z-dn.net/?f=3%5Csqrt%7B2%7D)
center is (-2,3)
find distance between (8,4) and (-2,3)
![D=\sqrt{(8-(-2))^2+(4-3)^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%288-%28-2%29%29%5E2%2B%284-3%29%5E2%7D)
![D=\sqrt{(8+2)^2+(1)^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%288%2B2%29%5E2%2B%281%29%5E2%7D)
![D=\sqrt{10^2+1}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B10%5E2%2B1%7D)
![D=\sqrt{100+1}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B100%2B1%7D)
![D=\sqrt{101}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B101%7D)
![r=3\sqrt{2}](https://tex.z-dn.net/?f=r%3D3%5Csqrt%7B2%7D)
≈4.2
![D=\sqrt{101}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B101%7D)
≈10.04
do r<D
(8,4) is outside the circle
Answer:
12/10=1.2
Step-by-step explanation:
You just move the decimal one place value to the left. so 12÷10=1.2 which is the same as 12/10=1.2
Im not sure but it should be 8.5
B:S = 4x:3x
4x - 3x = 3
x = 3
They were 12 & 9.
Add 5 to that.
So he’s now 17 and she’s 14