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Misha Larkins [42]
3 years ago
13

What do you need to evaluate claims made on a product label

Physics
1 answer:
iris [78.8K]3 years ago
4 0

Answer:

Product labels are important for explaining to consumers what they are buying. This can be a safety issue if customers have allergies or health concerns.

Explanation:

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5. What happens to the inductor current as time passes? 6. What happened to the inductor current when the supply voltage was tri
lawyer [7]

Answer:

i ran out of time

Explanation:

6 0
3 years ago
What happens to the charge on the conductive sphere when it is connected to a source of charge such as the electrostatic voltage
hichkok12 [17]

Answer and Explanation:

The charge on the conductive sphere spreads out non-uniformly over the surface of the sphere.

Normally, the charge on such spherical surface stay on this surface uniformly, but the presence of a voltage source tampers with that dynamic.

8 0
3 years ago
What kind of relationship does a human have with the bacteria that lives in her/his digestive tract?
Misha Larkins [42]
The one that both benefits each other is the one I think it's mutalistic
4 0
3 years ago
A semi-truck is traveling at 65mph on the freeway and you are traveling in your Ford
Ymorist [56]

Answer:

The vehicle with the most mass

Explanation:

Momentum is the quantity of motion in a body and it is dependent on its mass and velocity.

Momentum  = m x v

m is the mass

v is the velocity

Now,

Both mass and velocity are directly proportional to  momentum. Since the two bodies moves with the same velocity, the vehicle with the most mass will have the greatest momentum

7 0
3 years ago
If you place 48 cm object 15 m in front of a convex mirror of focal length 5 m, what is the magnification of the image?
Arisa [49]

Answer:

m = 0.25

Explanation:

Given that,

Object distance, u = -15cm

Height of the object, h = 48

Focal length, f = cm

We need to find the magnification of the image.

Let v is the image distance. Using mirror's equation.

\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}\\\\=\dfrac{1}{5}-\dfrac{1}{(-15)}\\\\=3.75\ cm

Magnification,

m=\dfrac{-v}{u}\\\\=\dfrac{-3.75}{-15}\\\\=0.25

Hence, the magnification of the image is 0.25.

7 0
3 years ago
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