Answer:
ΔU = -4.904 × 10^(5) J
Explanation:
We are given;
Heat transfer into the system;Q1 = 3.88 × 10^(6) J
Heat transfer out of the system;Q2 = 7.92 × 10^(6) J
Work done; W = 4.5 × 10^(5) J
Now, the net heat transfer is the heat transfer into the system minus the heat transfer out of the system. Thus;. Q = Q1 - Q2
Q = (3.88 × 10^(6)) - (7.92 × 10^(6))
Q = -4.04 × 10^(6) J
The formula for change in internal energy is given by the first law of thermodynamics:
ΔU = Q - W
ΔU = (-4.04 × 10^(6)) - 4.5 × 10^(5)
ΔU = -4.904 × 10^(5) J
The negative sign means loss of internal energy
Answer:
x is approximately 95.495
Explanation:
The given information are;
One lunar month = 30 days
The measured time between the first and third quarters = 14.9 days
Therefore, the angle of rotation for 30 days = 360°
The angle of rotation for 14.9 days = 14.9×360/30 = 178.8°
Therefore, whereby 2·θ = 178.8°
θ = 178.8°/2 = 89.4°
Therefore, given that the angle at the tangent from Sun to the Moon = 90°, we have;
The angle between the line from the Sun to the Moon = 90° - 89.4° = 0.6°
From sine rule, we have;
1/(sin 0.6) = x/(sin 90°)
x = (sin 90°)/(sin 0.6°) ≈ 95.495
x = 95.495.
Answer:
he spring provides the controlling torque. The air friction induces the damping torque, which opposes the movement of the coil. The repulsion type instrument is a non-polarized instrument, i.e., free from the direction of current passes through it. Thus, it is used for both AC and DC
Yes, two people can do different work and have the same power.
ANSWER:
Ca(OH)2 shows a decrease of solubility with the increase of temperature.
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