Earth exerts a 100 N gravitational force on a metal box. What is the magnitude of the gravitational force the metal box exerts o
1 answer:
We have that the magnitude of the gravitational force is mathematically given as
f=6.377N
<h3>Force</h3>Question Parameters:
Earth exerts a 100 N gravitational force on a metal box.
(Mass of the earth is 6e24 kg and radius of the earth is 6.4e6m.)
Generally the equation for the Gravitational mForce is mathematically given as
f=6.377N
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Answer:
The transverse displacement is
Explanation:
From the question we are told that
The generally equation for the mechanical wave is
The speed of the transverse wave is
The amplitude of the transverse wave is
The wavelength of the transverse wave is
At t= 0.150s , x = 1.51 m
The angular frequency of the wave is mathematically represented as
Substituting values
The propagation constant k is mathematically represented as
Substituting values
Substituting values into the equation for mechanical waves
Answer:
The work done on the wagon is 37 joules.
Explanation:
Given that,
The force applied by Charlie to the right, F = 37.2 N
The force applied by Sara to the left, F' = 22.4 N
We need to find the work done on the wagon after it has moved 2.50 meters to the right. The net force acting on the wagon is :
Work done on the wagon is given by the product of net force and displacement. It is given by :
W = 37 Joules
So, the work done on the wagon is 37 joules. Hence, this is the required solution.
The volume flow rates for ∆P is 6.81m³/s .
<h3>What is pressure?</h3>The amount of force applied on perpendicular to the surface of an object per unit area. The unit of it is pascal.
According to bernaulli's theorem theorem
P+1/2pV²+pgy = constant
where p fluid density
g is acceleration due to gravity, pressure at elevation,v is Velocity at elevation ,y is height of elevation.
As there are two tubes then the height of tube 1 is equal to height of tube two .
P1-P2=1/2p(Vd²-Vl²)
The flow rate of liquid is A1V1=A2V2 .
rest is attached in image
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