A=(vf-vi)/t
a=(50-25)/10
a=2.5m/s^2
a₀). You know ...
-- the object is dropped from 5 meters
above the pavement;
-- it falls for 0.83 second.
a₁). Without being told, you assume ...
-- there is no air anyplace where the marshmallow travels,
so it free-falls, with no air resistance;
-- the event is happening on Earth,
where the acceleration of gravity is 9.81 m/s² .
b). You need to find how much LESS than 5 meters
the marshmallow falls in 0.83 second.
c). You can use whatever equations you like.
I'm going to use the equation for the distance an object falls in
' T ' seconds, in a place where the acceleration of gravity is ' G '.
d). To see how this all goes together for the solution, keep reading:
The distance that an object falls in ' T ' seconds
when it's dropped from rest is
(1/2 G) x (T²) .
On Earth, ' G ' is roughly 9.81 m/s², so in 0.83 seconds,
such an object would fall
(9.81 / 2) x (0.83)² = 3.38 meters .
It dropped from 5 meters above the pavement, but it
only fell 3.38 meters before something stopped it.
So it must have hit something that was
(5.00 - 3.38) = 1.62 meters
above the pavement. That's where the head of the unsuspecting
person was as he innocently walked by and got clobbered.
Answer:
D: Conducts electrcity poorly
Explanation:
Most conductors are metals, and non- metals are insulators, therefore they dont conduct electricity
Answer:
E=1100V/m
Explanation:
Given required <u>solution</u>
V=6.6v E=? V=Ed ; V is the potential difference between
d=D/2=1.2cm/2=0.6cm=0.006m the halfway
E is the electric field between the two
plates.
d is the distance between the halfway.
So we can use the above formula to calculate the electric field.
V=Ed from this E=V/d substitute the values from the given equation.
E=6.6v/0.006m
E= 1100 v/m
The Hertzsprung- Russel diagram is used to how the relationship between the absolute magnitudes of stars and their effective temperatures.
