A 0.30-kg object is traveling to the right (in the positive direction) with a speed of 3.0 m/s. After a 0.20 s collision, the ob
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Answer:
The magnitude of displacement is 56.54 m
The direction of the displacement is along the line joining the two vectors.
Explanation:
The resultant displacement is always the line joining the initial and final position of the vectors.
As in figure,
the vector AB = 35 m
the vector BC = 15 m
the angle between AB and AC = 25' (minutes)
the resultant vector AC = ?
The resultant vector is given by the formula
AC² = AB² + BC² + 2 AB BC Cos θ
Substituting the values in the equations,
AC² = 35² + 15² + 2 x 35 x 15 x Cos 25'
= 56.54
Therefore, the magnitude of displacement is 56.54 m
The direction of the displacement is along the line joining the two vectors.
