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Bingel [31]
2 years ago
11

A 0.30-kg object is traveling to the right (in the positive direction) with a speed of 3.0 m/s. After a 0.20 s collision, the ob

ject is traveling to the left at 4.0 m/s. What is the magnitude of the impulse (in N-s) acting on the object
Physics
1 answer:
andre [41]2 years ago
5 0

Answer:

I = -2.1 kg.m/s

Explanation:

Given,

mass of the object,m = 0.30 Kg

initial speed, v_i = 3 m/s

time of collision = 0.20 s

final speed, v_f = -4 m/s

Impulse = change in momentum

I = m (v_f-v_i)

I = 0.30\times (-4-3)

I = -2.1 kg.m/s

Hence, impulse of the object is equal to I = -2.1 kg.m/s

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Answer:

f₂ = 468.67 Hz

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fb = 1.33 Hz

Another formula for beat frequency is:

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f₂ =  f₁ - fb

f₂ = 470 Hz - 1.33 Hz

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