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vovangra [49]
3 years ago
8

Name three common minerals in silicates

Physics
1 answer:
rjkz [21]3 years ago
3 0
Quartz, feldspa, mica, amphibole, pyroxene and olivine
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What was the result of the Mexican army's victory over the Texan garrison at the Alamo?
Nezavi [6.7K]

Answer:

The fallen defenders became heroes to the cause of Texan independence.

Explanation:

6 0
3 years ago
An object is in simple harmonic motion. Find an equation for the motion given that the frequency is 3⁄π and at time t = 0, y = 0
Delicious77 [7]

Answer: y(t)= 1/π^2 sin(6*π^2*t)

Explanation: In order to solve this problem we have to consider the general expression for a harmonic movement given by:

y(t)= A*sin (ω*t +φo) where ω is the angular frequency. A is the amplitude.

The data are: ν= 3π; y(t=0)=0 and y'(0)=6.

Firstly we know that 2πν=ω then ω=6*π^2

Then, we have y(0)=0=A*sin (6*π^2*0+φo)= A sin (φo)=0 then φo=0

Besides y'(t)=6*π^2*A*cos (6*π^2*t)

y'(0)=6=6*π^2*A*cos (6*π^2*0)

6=6*π^2*A then A= 1/π^2

Finally the equation is:

y(t)= 1/π^2 sin(6*π^2*t)

3 0
3 years ago
Read 2 more answers
How do you find the number of valence electrons in one atom of magnesium?
Iteru [2.4K]
Magnesium is element 12 in the periodic table and has 2 valance electrons.
7 0
4 years ago
A water strider bug is supported on the surface of a pond by surface tension acting along the interface between the water and th
Alik [6]

Answer:

minimum interface length = 1.36 mm

Explanation:

given data

weight of the bug = 10^{-4} N

solution

we will apply here Surface Tension formula that is

Surface Tension ,σ = Force ÷ length      ........................1

and we consider here surface tension for water is 7.34 × 10^{-2} N/m

so that here minimum interface length needed to support the bug is

minimum interface length = Force ÷ σ

minimum interface length = 10^{-4}  ÷ 7.34 × 10^{-2}

minimum interface length = 1.36 mm

                                                                                     

                                                                                     

4 0
3 years ago
A solenoid with 465 turns has a length of 8.00 cm and a cross-sectional area of 3.10 ✕ 10−9 m2. Find the solenoid's inductance a
hoa [83]

The solenoid's inductance and the average emf around the solenoid if the current changes from +3.50 A to −3.50 A in 7.83 ✕ 10−3 s will be 1.01 ×10⁻⁸ H and 9.02 × 10⁻² V.

<h3>What is a solenoid?</h3>

A coil of wire that carries an electric current is a solenoid. A solenoid is an electromagnet formed by a helical coil of wire.

Which generates a magnetic field when an electric current is passed through the coil.

A solenoid is a form of coil that produces a magnetic field when the electric current is passed through it. A solenoid is created when a conductive wire is used to make a loop.

Given data;

Turns ,N = 465

Length,L= 8.00 cm

Cross-sectional area,A = 3.10 ✕ 10−9 m2.

Solenoid's inductance, L=?

The average emf around the solenoid, E=?

Time of flow,t= 7.83 ✕ 10−3 s

Current changes from +3.50 A to −3.50 A

The inductance of the solenoid is found as;

\rm L =  \frac{\mu_0 AN^2}{L} \\\\ \rm L =  \frac{4 \times \pi \times 10^{-7}\times 3.0 \times 10^{-9} \times (465)^2 }{8.00 \times 10^{-2}} \\\\ L= 1.01 \times 10^{-8} \ H

The average emf around the solenoid is found as;

\rm e = L \frac{I_2-I_1}{t} \\\\ \rm e = 1.01 \times 10^{-8}  \times \frac{3.50-(-3.50)}{7.83 \times 10^{-3}} \\\\ e =9.02 \times 10^{-12} \  V

Hence, the solenoid's inductance will be 1.01× 10⁻⁸ H.

To learn more about the solenoid refer;

brainly.com/question/16015159

#SPJ1

3 0
2 years ago
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