Lets take 100 g of this compound,
so it is going to be 2.00 g H, 32.7 g S and 65.3 g O.
2.00 g H *1 mol H/1.01 g H ≈ 1.98 mol H
32.7 g S *1 mol S/ 32.1 g S ≈ 1.02 mol S
65.3 g O * 1 mol O/16.0 g O ≈ 4.08 mol O
1.98 mol H : 1.02 mol S : 4.08 mol O = 2 mol H : 1 mol S : 4 mol O
Empirical formula
H2SO4
Answer:
Sp3
Explanation:
Hydrocarbon can be defined as an organic compound that comprises of hydrogen and carbon only. Some examples of hydrocarbon are methane, butane, ethane, ethene, etc.
Hybridization can be defined as a phenomenon which involves the combination of two or more atomic orbitals to form the same number of hybrid orbitals, with each of the orbitals having the same shape and energy.
In Organic chemistry, ethane is considered to be a tetrahedral carbon and it's Sp3 hybridized.
A tetrahedral carbon typically comprises of four bonds that are 109. 5° apart while a linear carbon atom comprises of two (2) bonds that are 180° apart.
Hence, the molecule of ethane posses a Sp3 hybridization because it has four bonds arrange with a tetrahedral geometry.
ANSWER : 108 + 10 = 118
118 + ( 5 + 3 )
118 + 8 = <u>1</u><u>2</u><u>6</u>
<u>=</u><u> </u><u>1</u><u>2</u><u>6</u><u> </u><u>g</u>
Answer:
I do not know the Answer I'm just trying to get my point
Explanation:
Thank you
