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galina1969 [7]
3 years ago
12

Predict what the Co, levels will be when you are "old". How many plants/trees need to be planted now to keep carbon dioxide in t

he atmosphere at its current level or lower?
Chemistry
1 answer:
Anna [14]3 years ago
5 0

Answer:

A lot of them.

Explanation:

It would take hundreds of thousands of trees to clear all of the emmisions.

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If the number is not a proper coefficient, how would you make it one?
noname [10]
I’m pretty sure you add, multiply, subtract, & divide
3 0
1 year ago
A scientist is working in a lab and accidentally combines two liquids that quickly form a solution. Which process could be used
PIT_PIT [208]

Answer:

Distillation

Explanation:

The method of distillation can be used to separate the two liquids, if their boiling point is known. The liquid with lower boiling point will be evaporated and its vapours will be captured, while the liquid with higher boiling point will remail in the container in the liquid state.

7 0
2 years ago
How does the number of subatomic particles change as the carbon isotope<br> decays?
Rzqust [24]

Answer:

Explanation:

C decays by a process called beta decay. During this process, an atom of 14C decays into an atom of 14N, during which one of the neutrons in the carbon atom becomes a proton. This increases the number of protons in the atom by one, creating a nitrogen atom rather than a carbon atom.

5 0
2 years ago
What are some of the important funtions of cells
rosijanka [135]
In biological terms a cells main purpose is to survive but some important functions of cells are 1. Transports ( of molecules) 2. Chemical Reactions ( I.e Metabolism ) including energy conversion 3. reproduction hope this helps!
7 0
3 years ago
The edge length of the unit cell of KCl (NaCl-like structure, FCC) is 6.28 Å. Assuming anion-cation contact along the cell edge,
Mila [183]

Answer:

1.33 Å

Explanation:

Given that the edge length , a of the KCl which forms the FCC lattice = 6.28 Å

Also,

For the FCC lattice in which the anion-cation contact along the cell edge , the ratio of the radius of the cation to that of anion is 0.731.

Thus,

\frac {r^+}{r^-}=0.731 .................1

Also, the sum of the radius of the cation and the anion in FCC is equal to half of the edge length.

Thus,

r^++r^-=\frac {a}{2}  ...................2

Given that:

Cl^-\ (r^-) = 1.82\ \dot{A}

To find,

K^+\ (r^+) = ? \dot{A}

Using 1 and 2 , we get:

1.731\ r^+=0.731\times \frac {6.28}{2}

<u>Size of the potassium ion = 1.33 Å</u>

4 0
3 years ago
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