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Elena L [17]
3 years ago
5

Where is lipase produced

Chemistry
2 answers:
Ierofanga [76]3 years ago
8 0
It is made by cells in your stomach, but the main source is your pancreas, which is located in your digestive tract.

Answer: Pancreas
ad-work [718]3 years ago
8 0

Answer:

Lipases are widely found in animals, plants and microorganisms. In plants, seeds of oil crops contain more lipases, such as castor beans and rapeseed. When oil seeds germinate, lipases can work synergistically with other enzymes to catalyze the breakdown of oils and fats, generate sugar, and provide seeds nutrients and energy for germination. In animals, pancreas and adipose tissue contain more lipases. A small amount of lipase is exist in the intestinal fluid, which is used to supplement the deficiency of pancreatic lipase on the digestion of fat in meat animals. In the animals, various lipases control the processes of digestion, absorption, fat reconstitution and lipoprotein metabolism. If you want to learn more, click at the link to get more: https://www.creative-enzymes.com/similar/Lipase_408.html

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An independent variable is the variable changed or controlled in a scientific experiment to test the effects on the dependent variable. A dependent variable is the variable being tested and measured in a scientific experiment.
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You have a solution of 600 mg of caffeine dissolved in 100 mL of water. The partition coefficient for aqueous caffeine extracted
klio [65]

Answer:

159 mg caffeine is being extracted in 60 mL dichloromethane

Explanation:

Given that:

mass of caffeine in 100 mL of water =  600 mg

Volume of the water = 100 mL

Partition co-efficient (K) = 4.6

mass of caffeine extracted = ??? (unknown)

The portion of the DCM = 60 mL

Partial co-efficient (K) = \frac{C_1}{C_2}

where; C_1= solubility of compound in the organic solvent and C_2 = solubility in aqueous water.

So; we can represent our data as:

K=(\frac{A_{(g)}}{60mL} ) ÷ (\frac{B_{(mg)}}{100mL} )

Since one part of the portion is A and the other part is B

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A+B = 0.60

A= 0.60 - B

4.6=(\frac{0.6-B(mg)}{60mL} ) ÷ (\frac{B_{(mg)}}{100mL})

4.6 = \frac{(\frac{0.6-B(mg)}{60mL} )}{(\frac{B_{(mg)}}{100mL})}

4.6 × (\frac{B_{(mg)}}{100mL}) = (\frac{0.6-B(mg)}{60mL} )

4.6 B *\frac{60}{100} = 0.6 - B

2.76 B = 0.6 - B

2.76 + B = 0.6

3.76 B = 0.6

B = \frac{0.6}{3.76}

B = 0.159 g

B = 159 mg

∴ 159 mg caffeine is being extracted from the 100 mL of water containing 600 mg of caffeine with one portion of in 60 mL dichloromethane.

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