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Varvara68 [4.7K]
3 years ago
5

Can you determine the average atomic mass for an element if you know only the atomic number and mass number of an atom? If not,

what other information would you need?
Chemistry
1 answer:
Finger [1]3 years ago
8 0

<u>Answer:</u> To determine the average atomic mass, we require abundance of every isotope in the nature.

<u>Explanation:</u>

Average atomic mass is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

<u>For Example:</u> There are 3 isotopes of silicon, Si-28, Si-29 and Si-30.

We know that:

Average atomic mass of silicon = 28.086 amu

In order to calculate the average atomic mass of an element, we need the atomic mass of every isotope and also the abundance of every isotope in the nature.

Percentage abundance of Si-28 isotope = 92.2 %

Percentage abundance of Si-29 isotope = 4.7 %

Percentage abundance of Si-30 isotope = 3.1 %

Hence, to determine the average atomic mass, we require abundance of every isotope in the nature.

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A solution of aqueous ammonium sulfate has a mass of 482 grams. Calculate the mass of ammonium sulfate in solution if the mass p
umka2103 [35]

Answer:

The answer to your question is the mass of solute = 53.5 g

Explanation:

Data

mass of solution = 482 g

mass of solute = ?

mass percent = 11.1 %

Mass percent is a unit of concentration. It measures the mass of the solute divided by the total mass of the solution

Process

1.- Write the formula

        Mass percent = mass of solute / mass of solution x 100

-Solve for mass of solute

          mass of solute = Mass percent x mass of solution / 100

2.- Substitution

          mass of solute = 11.1 x 482 / 100

3.- Simplification

          mass of solute = 5350.2 / 100

4.- Result

          mass of solute = 53.5g

6 0
3 years ago
Consider the reaction: 2NO(g) + 2H2(g) → N2(g) + 2H2O(g) A suggested mechanism for this reaction follows: (1) NO(g) + NO(g) → N2
Dominik [7]

Hello. This question is incomplete. The full question is:

"Consider the following reaction.  2NO(g) + 2H2(g) → N2(g) + 2H2O(g)

A proposed reaction mechanism is:  NO(g) + NO(g) N2O2(g) fast  N2O2(g) + H2(g) → N2O(g) + H2O(g) slow  N2O(g) + H2(g) → N2(g) + H2O(g) fast

What is the rate expression?  A. rate = k[H2] [NO]2  B. rate = k[N2O2] [H2]  C. rate = k[NO]2 [H2]2  D. rate = k[NO]2 [N2O2]2 [H2]"

Answer:

A. rate = k[H2] [NO]2

Explanation:

A reaction mechanism is a term used to describe a set of phases that make up a chemical reaction. In these phases a detailed sequence of each step is shown, composed of several complementary reactions, which occur during a chemical reaction.

These mechanisms are directly related to chemical kinetics and allow changes in reaction rates to be observed in advance.

Reaction rate, on the other hand, refers to the speed at which chemical reactions occur.

Based on this, we can observe through the reaction mechanism shown in the question above, that the action "k [H2] [NO] 2" would have no changes in the reaction rate.

4 0
3 years ago
Will bromine react with sodium and why?
Archy [21]

<span><span>When you write down the electronic configuration of bromine and sodium, you get this

Na:
Br: </span></span>

<span><span />So here we the know the valence electrons for each;</span>

<span><span>Na:  (2e)
Br:  (7e, you don't count for the d orbitals)

Then, once you know this, you can deduce how many bonds each can do and you discover that bromine can do one bond since he has one electron missing in his p orbital, but that weirdly, since the s orbital of sodium is full and thus, should not make any bond.

However, it is possible for sodium to come in an excited state in wich he will have sent one of its electrons on an higher shell to have this valence configuration:</span></span>

<span><span /></span><span><span>

</span>where here now it has two lonely valence electrons, one on the s and the other on the p, so that it can do a total of two bonds.</span><span>That's why bromine and sodium can form </span>

<span>
</span>

4 0
3 years ago
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