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grandymaker [24]
2 years ago
5

A certain reaction has an activation energy of 25.88 kJ/mol. At what Kelvin temperature will the reaction proceed 6.00 times fas

ter than it did at 311 K?
Chemistry
1 answer:
Juli2301 [7.4K]2 years ago
5 0

Answer:hi

Explanation:

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Jet001 [13]

Answer:

Gravity

Explanation:

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3 years ago
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A gas occupies 25.3 at pressure of 790.5 mmHg. Determine the volume if the pressure is reduced to 8.04 mmHg
taurus [48]

Answer:

2487.51.

Explanation:

As per Boyle's law temperature remaining constant the volume of an ideal gas is inversely proportional to its pressure.

pV= k

therefore, p1V1 = p2V2

here V1 = 25.3, p2 = 8.04mm Hg

pressure p1 = 790.5 mm Hg

this means that

25.3×790.5 = 8.04V2

⇒V2= 2487.51

Hence, the required volume is, 2487.51.

5 0
3 years ago
0.50 g of hydrogen chloride (HCl) is dissolved in water to make 4.0 L of solution. What is the pH of the resulting hydrochloric
svlad2 [7]

Explanation:

Given the mass of HCl is ---- 0.50 g

The volume of solution is --- 4.0 L

To determine the pH of the resulting solution, follow the below-shown procedure:

1. Calculate the number of moles of HCl given by using the formula:

number of moles of a substance=\frac{given mass of the substance}{its molecular mass}

2. Calculate the molarity of HCl.

3. Calculate pH of the solution using the formula:

pH=-log[H^+]

Since HCl is a strong acid, it undergoes complete ionization when dissolved in water.

HCl(aq)->H^+(aq)+Cl^-(aq)

Thus, [HCl]=[H^+]

Calculation:

1. Number of moles of HCl given:

number of moles of a substance=\frac{given mass of the substance}{its molecular mass}\\=0.50g/36.5g/mol\\=0.0137mol

2. Concentration of HCl:

Molarity of HCl=\frac{number of moles of HCl}{its molar mass}\\=\frac{0.0137 mol}{4.0 L} \\= 0.003425 M

3. pH of the solution:

pH=-log[H^+]\\=-log(0.003425)\\=2.47

Hence, pH of the given solution is 2.47.

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3 years ago
Which of these bonds should be classified as ionic?
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Answer:

Na-O

Be-S

Explanation:

ionic bonds= metal and non metal

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True I think I’m not for sure
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