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grandymaker [24]

2 years ago

5

A certain reaction has an activation energy of 25.88 kJ/mol. At what Kelvin temperature will the reaction proceed 6.00 times fas

ter than it did at 311 K?

1 answer:

Juli2301 [7.4K]2 years ago

5 0

Answer:hi

Explanation:

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A galvanic cell consists of one half-cell that contains Ag(s) and Ag+(aq), and one half-cell that contains Cu(s) and Cu2+(aq). W

Agata [3.3K]

Answer : The 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Explanation :

Galvanic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the voltaic cell or electrochemical cell.

In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

We are taking the value of standard reduction potential form the standard table.

$E^0_{[Ag^{+}/Ag]}=+0.80V$

$E^0_{[Cu^{2+}/Cu]}=+0.34V$

In this cell, the component that has lower standard reduction potential gets oxidized and that is added to the anode electrode. The second forms the cathode electrode.

The balanced two-half reactions will be,

Oxidation half reaction (Anode) : $Cu(s)\rightarrow Cu^{2+}(aq)+2e^-$

Reduction half reaction (Cathode) : $Ag^{+}(aq)+e^-\rightarrow Ag(s)$

Thus the overall reaction will be,

$Cu(s)+2Ag^{+}(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)$

From this we conclude that, 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Hence, the 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

7 0

3 years ago

When 250 ml of water is added to 35 ml of 0.2 M HCl

Paladinen [302]

Assuming that you’re looking for the concentration of water in the solution, then it would be 0.028 M.

You would have to use the formula:
c1v1 = c2v2, where c =concentration and
v = volume

C1 = ?
V1 = 250 mL
C2 = 0.2 M
V2 = 35 mL

C1 x 250 mL = 0.2 M x 35 mL

C1 = (0.2 M x 35 mL) / 250 mL

C1 = 0.028 M of water added to 35mL of 0.2M HCl

Therefore, there is 0.028 M of water added to 35mL of 0.2M HCl

8 0

3 years ago

Read 2 more answers

The temperature of a sample of water changes from 10°C to 20°C when the water absorbs 100 calories of heat. What is the mass of

Vlad1618 [11]

Answer:

10 g

Explanation:

Right from the start, just by inspecting the values given, you can say that the answer will be

10 g

.

Now, here's what that is the case.

As you know, a substance's specific heat tells you how much heat is needed to increase the temperature of

1 g

of that substance by

1

∘

C

.

Water has a specific heat of approximately

4.18

J

g

∘

C

. This tells you that in order to increase the temperature of

1 g

of water by

1

∘

C

, you need to provide

4.18 J

of heat.

Now, how much heat would be required to increase the temperature of

1 g

of water by

10

∘

C

?

Well, you'd need

4.18 J

to increase it by

1

∘

C

, another

4.18 J

to increase it by another

1

∘

C

, and so on. This means that you'd need

4.18 J

×

10

=

41.8 J

to increase the temperature of

1 g

of water by

10

∘

C

.

Now look at the value given to you. If you need

41.8 J

to increase the temperature of

1 g

of water by

10

∘

C

, what mass of water would require

10

times as much heat to increase its temperature by

10

∘

C

?

1 g

×

10

=

10 g

And that's your answer.

Mathematically, you can calculate this by using the equation

q

=

m

⋅

c

⋅

Δ

T

, where

q

- heat absorbed/lost

m

- the mass of the sample

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as final temperature minus initial temperature

Plug in your values to get

418

J

=

m

⋅

4.18

J

g

∘

C

⋅

(

20

−

10

)

∘

C

m

=

418

4.18

⋅

10

=

10 g

5 0

2 years ago

Prandtl number in heat transfer analogues to which dimension less number in mass transfer. a) Schmidt number b) Sherwood number

Cloud [144]

Answer:

a) Schmidt number

Explanation:

Prandtl number in heat transfer is analogues to Schmidt number in mass transfer.

Prandtl number in heat transfer is the ration of momentum diffusivity to the heat diffusivity.

$P_r = \frac{\nu}{\alpha}$

Whereas, Schmidt number in mass transfer is the ratio of momentum diffusivity to the mass diffusivity.

$S_c= \frac{\nu}{\nu_{AB}}$

5 0

2 years ago

Enter an abbreviated electron configuration for magnesium: Express your answer in complete form, in order of increasing energy.

stiks02 [169]

Answer:

1s2, 2s2,2p6,3s2

Explanation:

6 0

3 years ago

Read 2 more answers