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4 years ago

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When a star dies which of these celestial objects is it most likely to help create ?

2 answers:

Naily [24]4 years ago

8 0

The answer is B.) a star

did this help?

wariber [46]4 years ago

4 0

The correct answer is option 2, that is, a star.

Stars die as they consume all the fuel, which permits a star to go through the process of fusion. A star is formed majorly of helium and hydrogen. Once a star uses all the hydrogen, the star begins to die. When a normal-sized star dies, the core eventually cools into a white dwarf, and then into a black dwarf.

White dwarf refers to a very dense and small star, which is usually of the size of a planet. A white dwarf is produced when a low-mass star has used all its central nuclear fuel and lost its outer enveloping as a planetary nebula.

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frosja888 [35]

Answer:

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Explanation:

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3 years ago

Read 2 more answers

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Reika [66]

Answer : The enthalpy change for the process is 52.5 kJ/mole.

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the solution

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]$

where,

q = heat released by the reaction

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the solution

$c_1$ = specific heat of calorimeter = $12.1J/^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_2$ = mass of water or solution = $Density\times Volume=1/mL\times 100.0mL=100.0g$

$\Delta T$ = change in temperature = $T_2-T_1=(26.3-20.2)^oC=6.1^oC$

Now put all the given values in the above formula, we get:

$q=[(12.1J/^oC\times 6.1^oC)+(100.0g\times 4.18J/g^oC\times 6.1^oC)]$

$q=2623.61J$

Now we have to calculate the enthalpy change for the process.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat released = 2626.61 J

n = number of moles of copper sulfate used = $Concentration\times Volume=1M\times 0.050L=0.050mole$

$\Delta H=\frac{2623.61J}{0.050mole}=52472.2J/mole=52.5kJ/mole$

Therefore, the enthalpy change for the process is 52.5 kJ/mole.

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Answer:

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Explanation:

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Explanation:

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