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bulgar [2K]
3 years ago
8

Ocean exploration is limited by

Chemistry
2 answers:
Alex777 [14]3 years ago
8 0
It is limited by the depth divers and equipment can go. 
Contact [7]3 years ago
4 0

Answer:

Check explanation

Explanation:

From the above, we can see that the question is not complete, I have tried looking out if I can find the exact question elsewhere but, unfortunately I can't. Let us try to familiarize ourselves with OCEAN EXPLORARION and its LIMITATIONS so that if you see a question similar to this , you will be able to handle it properly.

So, what is OCEAN EXPLORARION?.

OCEAN EXPLORARION is the thorough examination or discoveries of mysterious things in the water body. Water as we know occupy about seventy(70) percent of the Earth's total space,a very large space!, So there is a need to explore it for the benefit of mankind.

Ocean exploration is never a new thing in the twenty first century, it has been for ages. Ocean explorations has been done by Polynesians, Portuguese, Phoenicians and so on. Some of the importance of OCEAN EXPLORATION are;

(1). We can use the information gotten from ocean exploration to determine the conditions in oceans and how it can affect humans life. For example, we can use it to predict earthquakes and tsunamis and climate change.

(2).For research and exploration sake, It is easy to explore oceans than some other exploratios like the space exploration, and obviously, it will be more cheaper than space exploration.

THE LIMITATIONS OF OCEAN EXPLORARION; Ocean exploration, despite its advantages it still has limitations. Its limitations are;

(1). The ocean is a very big place and it will take a long time to fully explore it all.

(2). There are little submersibles that can go deep inside the ocean because As one goes deep, the pressure increases, and there are little numbers of manned submersibles that can go deep down there.

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C.

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Four gases were combined in a gas cylinder with these partial pressures: 3.5 atm N2, 2.8 atm O2, 0.25 atm Ar, and 0.15 atm He.
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This can be solved using Dalton's Law of Partial pressures. This law states that the total pressure exerted by a gas mixture is equal to the sum of the partial pressure of each gas in the mixture as if it exist alone in a container. In order to solve, we need the partial pressures of the gases given. Calculations are as follows:

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Titanium is a transition metal used in many alloys because it is extremely strong and lightweight. Titanium tetrachloride (TiCl4
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Answer:

a) 226.6 grams of Cl₂

b) 19.2 grams of C

c) 303.2 grams of TiCl₄ and 70.4 grams of CO₂

Explanation:

The balanced chemical reaction is the following:

TiO₂(s) + C(s) + 2 Cl₂(g) → TiCl₄(s) + CO₂(g)

(a) What mass of Cl₂ gas is needed to react with 1.60 mol TiO₂?

From the chemical equation, 1 mol of TiO₂ reacts with 2 moles of Cl₂. So, the stoichiometric ratio is 2 mol Cl₂/1 mol TiO₂. We multiply this ratio by the moles of TiO₂ we have to calculate the moles of Cl₂ we need:

1.60 mol TiO₂ x 2 mol Cl₂/1 mol TiO₂ = 3.2 mol Cl₂

Now, we convert from moles to mass by using the molecular weight (MW) of Cl₂:

MW(Cl₂) = 35.4 g/mol x 2 = 70.8 g/mol

mass of Cl₂= 3.2 mol x 70.8 g/mol = 226.6 g

<em>Therefore, 226.6 grams of Cl₂ are needed to react with 1.6 mol of TiO₂. </em>

(b) What mass of C is needed to react with 1.60 mol of TiO₂?

From the chemical equation, 1 mol of TiO₂ reacts with 1 moles of C(s). So, the stoichiometric ratio is 1 mol C/1 mol TiO₂. We multiply this ratio by the moles of TiO₂ we have to calculate the moles of C(s) we need:

1.60 mol TiO₂ x 1 mol C(s)/1 mol TiO₂ = 1.60 mol C(s)

So, we convert the moles of C(s) to grams as follows:

MW(C) = 12 g/mol

1.60 mol x 12 g/mol = 19.2 g C(s)

<em>Therefore, a mass of 19.2 grams of C is needed to react with 1.60 mol of TiO₂. </em>

(c) What is the mass of all the products formed by reaction with 1.60 mol of TiO₂?

From the chemical equation, we can notice that 1 mol of TiO₂ produces 1 mol of TiCl₄ and 1 mol of CO₂. So, from 1.60 moles of TiO₂, 1 mol of each product will be produced:

1 mol TiO₂/1 mol TiCl₄ ⇒ 1.60 mol TiO₂/1.60 mol TiCl₄

1 mol TiO₂/1 mol CO₂ ⇒ 1.60 mol TiO₂/1.60 mol CO₂

Finally, we convert the moles to grams by using the molecular weight of each compound:

MW(TiCl₄) = 47.9 g/mol Ti + (35.4 g/mol x 4 Cl) = 189.5 g/mol

1.60 mol x 189.5 g/mol = 303.2 g

MW(CO₂) = 12 g/mol C + (16 g/mol x 2 O) = 44 g/mol

1.60 mol x 44 g/mol = 70.4 g

<em>Therefore, from the reaction of 1.60 mol of TiO₂ are formed 303.2 grams of TiCl₄ and 70.4 grams of CO₂.</em>

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