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Evgen [1.6K]
3 years ago
10

The decomposition of in solution in carbon tetrachloride is a first-order reaction: The rate constant at a given temperature is

found to be . If the initial concentration of is 0.200 M, what is its concentration after exactly 10 minutes have passed?
Chemistry
2 answers:
Elan Coil [88]3 years ago
6 0

Answer:

see below

Explanation:

The rate constant is missing in question, but use C(final) = C(initial)e^-kt = 0.200M(e^-k·10). Fill in k and compute => remaining concentration of reactant

Crazy boy [7]3 years ago
4 0

Answer:

C(initial)e^-kt = 0.200M(e^-k·10).

Explanation:

The rate constant is missing in question, but use C(final) = C(initial)e^-kt = 0.200M(e^-k·10).

Fill in k and compute => remaining concentration of reactant

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A sample of a food label is shown below.
White raven [17]

Answer:

A) It's correctly written

B) 77%

C) 835 calories

Explanation:

A) From online sources, we have number of calories as follows;

Fats: 9 calories per gram

Protein; 4 calories per gram

Carbs; 4 calories per gram

Total calories for each;

Total fat = 3 × 9 = 27 calories

Total protein = 3 × 4 = 12 calories

Total carbs = 32 × 4 = 128 calories

(sugar and dietary Fibre are classified as carbohydrates and so total carbs takes care of their calories).

Thus, total number of calories per serving = 27 + 12 + 128 = 167 calories per serving which is same as what is given.

B) percent from carbohydrates per serving = total calories from carbs/total number of calories per serving × 100% = 128/167 × 100% ≈ 77%

C) One box contains 5 servings. Thus total number of calories per box = 167 × 5 = 835 calories

8 0
3 years ago
What is the freezing point of glucose?
Triss [41]

Answer:

In Fahrenheit it is 294.8°F and in Celsius it is 146°C.

7 0
2 years ago
A solution made by dissolving 33 mg of insulin in 6.5 mL of water has an osmotic pressure of 15.5 mmHg at 25°C. Calculate the mo
Liula [17]

<u>Answer:</u> The molar mass of the insulin is 6087.2 g/mol

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

Or,

\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT

where,

\pi = osmotic pressure of the solution = 15.5 mmHg

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (insulin) = 33 mg = 0.033 g   (Conversion factor: 1 g = 1000 mg)

Volume of solution = 6.5 mL

R = Gas constant = 62.364\text{ L.mmHg }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

15.5mmHg=1\times \frac{0.033\times 1000}{\text{Molar mass of insulin}\times 6.5}\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 298K\\\\\text{molar mass of insulin}=\frac{1\times 0.033\times 1000\times 62.364\times 298}{15.5\times 6.5}=6087.2g/mol

Hence, the molar mass of the insulin is 6087.2 g/mol

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Answer:

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3 years ago
How many independent variables can you have during an experiment? A: 1 B: 2 C: as many as you would like D: the same amount as t
lianna [129]

Answer: a

Explanation: its 1

3 0
3 years ago
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