lol what the heck dude it's eVaPoRaTioN
AH1 = m * c1 * AT1 calculate this for ice (-25C to 0C) AH2 = AHfus(1 mole)=6.01 kJ = 6010 J AH3 = m *c3 * AT3 calculat this for water (0C to 100C) AH4 = AHvap(1mole)=40.67 kJ = 40670 J AH5= m * c5 * AT5 calculate this for steam (100C to 125C)
Sum ---- AH1+AH2+AH3+AH4+AH5
Data m=18g (1mole water)
c1=specific heat ice= 2.09 J/g K c3=specific heat water= 4.18 J/g K c5=specific heat steam= 1.84 J/g K
AT = (Tend - Tinitial) as this is a difference between temperatures it doesn't matter the units Celsius or Kelvin. Kelvin (K)=Celsius (C)+273.15
AT1 = 0C - (-25C)= 25C= 273.15K - 248.15K= 25K AT3= 100C - 0C = 100C= 100K AT5= 125C - 100C= 25C=25K
Answer:
The mass of gold is found to be 310.34 g.
Explanation:
We have:
Specific heat of gold = C = 0.130 J/g.°C
Heat = H = 468 J
Change in Temperature = ΔT = 33.2 °C - 21.6 °C = 11.6 °C
Now, to find mass of gold we first calculate the amount of heat required to heat the unit mass of gold to specified temperature:
Mass Specific Heat = C * ΔT
Mass Specific Heat = (0.130 J/g.°C)(11.6 °C)
Mass Specific Heat = 1.508 J/g
Now, for the mass of gold (m):
mass of gold = Heat/Mass Specific Heat
mass of gold = 468 J/1.508 J/g
<u>mass of gold = 310.34 g</u>
Answer:
The rocket is now too heavy to reach its destination.
girl i need help with this toofrom the electrochem lab :(
funny how i found this