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3 years ago

1.

Chemistry

2 answers:

Nata [24]3 years ago

8 0

Oregon trail would be the best answer

irga5000 [103]3 years ago

3 0

1: A. National Road

2: B. Mostly by barge across the Chesapeake and Ohio Canal

3: C. Wilderness Road

4: C. Transcontinental Railroad

5. C. Gila Trail

I took the quiz and I have confirmed that these are the correct answers, I hope this assists you.

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c. The reaction Br2 (l) --> Br2 (g) has ΔH = 30.91 kJ/mol and ΔS = 93.3 J/mol·K. Use this information to show (within close a

egoroff_w [7]

Answer:

The answer to your question is given below.

Explanation:

From the question given above, the following data were obtained:

Br₂ (l) —> Br₂(g)

Enthalpy change (ΔH) = 30.91 KJ/mol

Entropy change (ΔS) = 93.3 J/mol·K

Boiling temperature (T) =?

Next, we shall convert 30.91 KJ/mol to J/mol. This can be obtained as follow:

1 KJ/mol = 1000 J/mol

Therefore,

30.91 KJ/mol = 30.91 × 1000

30.91 KJ/mol = 30910 J/mol

Thus, 30.91 KJ/mol is equivalent to 30910 J/mol.

Finally, we shall determine the boiling temperature of bromine. This can be obtained as follow:

Enthalpy change (ΔH) = 30910 J/mol

Entropy change (ΔS) = 93.3 J/mol·K

Boiling temperature (T) =?

ΔS = ΔH / T

93.3 = 30910 / T

Cross multiply

93.3 × T = 30910

Divide both side by 93.3

T = 30910 / 93.3

T = 331.29 K

Thus, the boiling temperature of bromine is 331.29 K

6 0

3 years ago

This reaction supports the Law of Conservation of Mass (hint: is the equation balanced?):

enyata [817]

Answer:

False

Explanation:

Left:

K = 2 atoms

O = 1 atoms

H = 1 atoms

Right: 

K = 2 atoms

O = 1 atoms

H = 2 atoms

O = 1 atoms

As you can see both sides do not have the same amount of atoms, therefore it is not balanced.

<h3>Hope this Helps!!</h3>

7 0

3 years ago

The density of thorium, which has the FCC structure, is 11.72 g/cm3. The atomic weight of thorium is 232 g/mol. Calculate (a) th

seropon [69]

Answer:

(a) a = 5.08x10⁻⁸ cm

(b) r = 179.6 pm

Explanation:

(a) The lattice parameter "a" can be calculated using the following equation:

$\rho = \frac{(N atoms/cell)*m}{V_{c}*N_{A}}$

where ρ: is the density of Th = 11.72 g/cm³, N° atoms/cell = 4, m: is the atomic weight of Th = 232 g/mol, Vc: is the unit cell volume = a³, and $N_{A}$ : is the Avogadro constant = 6.023x10²³ atoms/mol.

Hence the lattice parameter is:

$a^{3} = \frac{(N atoms/cell)*m}{\rho *N_{A}} = \frac{4 atoms*232 g/mol}{11.72 g/cm^{3} *6.023 \cdot 10^{23} atoms/mol} = 1.32 \cdot 10^{-22} cm^{3}$

$a = \sqrt[3]{1.32 \cdot 10^{-22} cm^{3}} = 5.08 \cdot 10^{-8} cm$

(b) We know that the lattice parameter of a FCC structure is:

$a = \frac{4r}{\sqrt{2}}$

where r: is the atomic radius of Th

Hence, the atomic radius of Th is:

$r = \frac{a*\sqrt{2}}{4} = \frac{5.08 \cdot 10^{-8} cm*\sqrt{2}}{4} = 1.796 \cdot 10^{-8} cm = 179.6 pm$

I hope it helps you!

4 0

3 years ago

Read 2 more answers

Divide a 7 inch line into three parts so that each part is longer than than the one before it

olga nikolaevna [1]

The answer is 2.33 when you multiply bi 3 its 6.99

3 0

3 years ago

Which of the following is not an adaptation of California thrashers to life in the chaparral biome? a. a long, curved beak for s

BaLLatris [955]

Answer:

Explanation:

i think option D

hope this helps

4 0

3 years ago

Read 2 more answers