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Nutka1998 [239]
3 years ago
9

A standardized​ exam's scores are normally distributed. In a recent​ year, the mean test score was and the standard deviation wa

s . The test scores of four students selected at random are ​, ​, ​, and . Find the​ z-scores that correspond to each value and determine whether any of the values are unusual.

Mathematics
1 answer:
kiruha [24]3 years ago
8 0

Answer:

The following are the solution to this question:

Step-by-step explanation:

In the given question, some of the values are missing which is defined in the attached file please find it.

In this question, the data is used to represent a standardized​ exam's scores, which is normally spread out into the test score that is  1530 and its standard deviation 316.  

Formula:

\to z=\frac{X- \mu}{\sigma } \\

If the value of z-score= 1930

       \to z =\frac{1930- 1530}{316 } \\\\ \to z  =\frac{400}{316 } \\\\ \to z = 1.27

The z-score is 1.27

If the value of z-score= 1250

       \to z =\frac{1250- 1530}{316 } \\\\ \to z  =\frac{-280}{316 } \\\\ \to z = -0.886

The z-score is -0.886

If the value of z-score= 2250

       \to z =\frac{2250- 1530}{316 } \\\\ \to z  =\frac{720}{316 } \\\\ \to z = 2.27

The z-score is = 2.27

If the value of z-score= 1420

       \to z =\frac{1420- 1530}{316 } \\\\ \to z  =\frac{-110}{316 } \\\\ \to z = -0.348

The z-score is = -0.348

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Answer:

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Step-by-step explanation:

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