All categories

4 years ago

An example of a Natural electric field is

Physics

2 answers:

liberstina [14]4 years ago

6 0

Answer:

Lightning

Explanation

user100 [1]4 years ago

5 0

Possibly an eel
I’m not too sure ... but definitely lightning

You might be interested in

What is the frequency of a 5 m wave traveling at the speed of 200 m/s

morpeh [17]

Explanation:

f=v/wavelength

=200/5

=40Hz

7 0

4 years ago

Answer all of them an you will get the brain list

Vlad [161]

Answer:

4. Force = 178.6 Newton.

5. Acceleration = 2.28 m/s².

6. Force = 178.6 Newton.

Explanation:

4. Given the following data;

Acceleration = 3.8 m/s²

Mass = 47kg

Force = mass * acceleration

Force = 47 * 3.8

<em>Force = 178.6 Newton. </em>

5. Given the following data;

Force = 785N

Mass = 345kg

Acceleration = force/mass

Acceleration = 785/345

<em>Acceleration = 2.28 m/s²</em>

6. Given the following data;

Acceleration = 6m/s²

Force = 32N

Mass =force/acceleration

Mass = 32/6

<em>Mass = 5.33 kilograms </em>

5 0

3 years ago

Which of the following is an example of a chemical change?

ss7ja [257]

Answer:

Burning Paper

Explanation:

This is a chemical reaction, because new substances are formed

6 0

3 years ago

A go cart with a mass of 60 kg is moving at a rate of 10 m/s. How much Kinetic Energy does the go cart have?

maria [59]

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

$k = \frac{1}{2} m {v}^{2} \\$

m is the mass in kg

v is the velocity in m/s

From the question

m = 60 kg

v = 10 m/s

We have

$k = \frac{1}{2} \times 60 \times {10}^{2} \\ = 30 \times 100 \\ = 3000$

We have the final answer as

Hope this helps you

6 0

3 years ago

Read 2 more answers

A billiard ball is moving in the x-direction at 30.0 cm/s and strikes another billiard ball moving in the y-direction at 40.0 cm

PSYCHO15rus [73]

Explanation:

Given that,

Initial speed of the billiard ball 1, u = 30i cm/s

Initial speed of another billiard ball 2, u' = 40j cm/s

After the collision,

Final speed of first ball, v = 50 cm/s

Final speed of second ball, v' = 0 (as it stops)

Let us consider that both balls have same mass i.e. m

Initial kinetic energy of the system is :

$K_i=\dfrac{1}{2}mu^2+\dfrac{1}{2}mu'^2\\\\K_i=\dfrac{1}{2}m(u^2+u'^2)\\\\K_i=\dfrac{1}{2}m((30)^2+(40)^2)\\\\K_i=1250m\ J$

Final kinetic energy of the system is :

$K_f=\dfrac{1}{2}mv^2+\dfrac{1}{2}mv'^2\\\\K_f=\dfrac{1}{2}m(v^2+v'^2)\\\\K_f=\dfrac{1}{2}m((50)^2+(0)^2)\\\\K_f=1250m\ J$

The change in kinetic energy of the system is equal to the difference of final and initial kinetic energy as :

$\Delta K=K_f-K_i\\\\\Delta K=1250m-1250m\\\\\Delta K=0$

So, the change in kinetic energy of the system as a result of the collision is equal to 0.

7 0

4 years ago