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Ad libitum [116K]

3 years ago

5

ln the constellation of Orion, you can see a group of stars and other objects that appear in the shape of a sword. Ln the middle

of the sword, a bright "fuzzy star" appears. Astronomers looking at this object through telescopes refer to it as a "stellar nursery."What is another name for this object?

1 answer:

bagirrra123 [75]3 years ago

7 0

Answer:

Nebula

Explanation:

Given that in the constellation of Orion, you can see a group of stars and other objects that appear in the shape of a sword. Ln the middle of the sword, a bright "fuzzy star" appears. Astronomers looking at this object through telescopes refer to it as a "stellar nursery." Another name for this object is called NEBULA.

The space where new stars are forming anew is known as nebulae

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A 2.2 kg object is whirled in a vertical circle whose radius is 1.0 m. If the time of one revolution is 0.97 s,

strojnjashka [21]

Answer:

The tension in the string at the top = $71 N$

The tension in the string at the top = $1.1 \times 10^{-2} N$

Explanation:

a) at the top

$F_{cent} = F_g +F_T$ ----------------------(1)

Where,

$F_{cent}$ is the centripetal force

$F_g$ is the gravitational force

$F_T$ force due to tension

From (1)

$F_T = F_{cent} - F_g$

$F_T = \frac{ 4\pi^2 Rm}{T^2} -mg$

where

R is the radius

m is the mass

T is the time taken for one revolution

g is the acceleration due to gravity

On Substituting the values

$F_T = \frac{4 (3.14)^2 (1.0)}{(0.97)^2} -(2.2 \times9.8)$

$F_T$ = 70.7259N

$F_T$ =71N

b) at the bottom

On Substituting the values

$F_{cent} = -F_g +F_T$

$F_T = F_{cent}- F_g$

$F_T = \frac{ \pi^2 Rm}{T^2} +mg$

$F_T = \frac{4 (3.14)^2 (1.0)}{(0.97)^2} +(2.2 \times9.8)$

$F_T = 113.8899N$

$F_T = 1.1 \times 10^{-2}$

8 0

3 years ago

When a permanent magnet picks up an iron nail, the nail also becomes a magnet. How does the magnetized nail differ from an elect

Yuri [45]

Hi u need help still?

4 0

2 years ago

An electric heater is rated at 1400 W, a toaster is rated at 1150 W, and an electric grill is rated at 1560 W. The three applian

gayaneshka [121]

Answer:

The current in the heater is 12.5 A

Explanation:

It is given that,

Power of electric heater, P₁ = 1400 W

Power of toaster, P₂ = 1150 W

Power of electric grill, P₃ = 1560 W

All three appliances are connected in parallel across a 112 V emf source. We need to find the current in the heater. We know that in parallel combination of resistors the current flowing in every branch of resistor divides while the voltage is same.

Electric power, $P_1=V\times I_1$

$I_1=\dfrac{P_1}{V}$

$I_1=\dfrac{1400\ W}{112\ V}$

$I_1=12.5\ A$

So, the current in the heater is 12.5 A. Hence, this is the required solution.

8 0

3 years ago

In being served, a tennis ball is accelerated from rest to a speed of 42.1 m/s. The average power generated during the serve is

hoa [83]

Answer:

Force F = 69.35 N

Explanation:

given data

Ball Initial speed u = 0

Ball Final speed v = 42.1 m/s

average power generate = 2920 W

solution

Power generate is express as

P= $\frac{W}{t}$ ..............1

here W is work done and t is time

and work w = F × d

so

P= $\frac{Fd}{t}$

and we know speed v = $\frac{d}{t}$

so here

Power P = F × v

put here value and we get force

Force F = $\frac{2920}{42.1}$

Force F = 69.35 N

8 0

3 years ago

Car A is traveling west at 40 mi/h and car B is traveling north at 40 mi/h. Both are headed for the intersection of the two road

Gwar [14]

Explanation:

It is given that,

$\frac{dx}{dt}$ = -40 mi/h, $\frac{dx}{dt}$ = -40 mi/h

The negative sign indicates that x and y are decreasing.

We have to find $\frac{dz}{dt}$ . Equation for the given variables according to the Pythagoras theorem is as follows.

$z^{2} = x^{2} + y^{2}$

Now, we will differentiate each side w.r.t 't' as follows.

$2z\frac{dz}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt}$

or, $\frac{dz}{dt} = \frac{1}{z}(x\frac{dx}{dt} + y\frac{dy}{dt})$

So, when x = 4 mi, and y = 3 mi then z = 5 mi.

As, $\frac{dz}{dt} = \frac{1}{z}(x\frac{dx}{dt} + y\frac{dy}{dt})$

= $\frac{1}{5}(4 \times (-40) + 3 \times (-40))$

= $\frac{-140 - 120}{5}$

= 52

Thus, we can conclude that the cars are approaching at a rate of 52 mi/h.

7 0

3 years ago