Answer:
a. C(F) = (5/9).F - (160/9)
b. They both readings are equal at C = F = - 40
Explanation:
They are telling us that we are looking for a linear function
If C(F) = a.F + b is the linear function, we use the data to find a and b
C(32) = a.32 + b
0 = a.32 + b
b = - (a.32) (1)
And then
C(212) = a.212 + b
100 = a.212 + b (2)
replacing (1) in (2) we obtain
100 = a.212 + [-(a.32)]
100 = a.212 - a.32
100 = 180.a
a = 100/180
a = 5/9
If a = 5/9 then b = -(a.32)
b = - (5/9).32
b = - (160/9) and the linear function is
C(F) = (5/9).F - (160/9)
For b. they are asking us for a X reading. We must equalize C and F
X = (5/9).X - (160/9)
(4/9).X = - (160/9)
X = -40
C = F at temperature X = - 40
#3). Your drawing in the lower right corner is correct. You're headed down the right road, but ran out of gas and just stopped.
Radius of the circle = 1.5 km
Circumference of the whole circle = (2·π·radius) = 9.42 km
Distance = 3/4 of the way around it = 7.07 km .
Displacement = the straight line from the West point to the North point. The straight-line length is 2.12 km; the straight-line direction from start to finish is Northeast (45°). I'll let you figure out why these numbers.
#4). What if you walk 1 mile East and then 1 mile West ? You got a good workout, and you're back home where you started ! Your distance is 2 miles, and your displacement is zero.
The whale had a good workout too. She swam (6.9 + 1.8 + 3.7) = 12.4 km. She's sweating and tired. Her total distance during that workout is 12.4 km.
Her displacement is the line from start-point to end-point. How she got there doesn't matter, so swimming 1 km East and then swimming 1 km West cancel out, and have no effect on the displacement.
(6.9E + 1.8W + 3.7E) = (10.6 E) + (1.8 W) . . . That adds up to 8.8 East ! That's where she ends up. That's her displacement ... 8.8 km East of where she started. Since we're only talking about displacement, we don't care HOW she got there. She might have been swimming big 20-km circles all day. We don't know. All we know is that she ended up 8.8 km East of where she started.
The net force on q2 will be 1.35 N
A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction.
Given Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C, and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m.
We have to find the net force on q2
At first we will find Force due to q1
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²
F = 450 × 10⁻³
F₁ = 0.45 N (+)
Now we will find Force due to q2
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²
F = 1800 × 10⁻³
F₂ = 1.8 N (-)
So net force (F) will be
F = F₂ - F₁
F = 1.8 - 0.45
F = 1.35 N
Hence the net force on q2 will be 1.35 N
Learn more about force here:
brainly.com/question/25573309
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Answer:
I Guess the answer is B
Explanation:
Are those Answer choices or instructions?
Answer:
Newton's third law, if i'm not mistaken.
Explanation:
Any action that occurs will have a opposite and equal action. The greater the force u apply to the wall, the greater the force the wall exerts back at you, hence why ur hands become red if u try pushing extremely hard on the wall.
