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1 year ago

A net force of 2800 N is applied to a 1400 kg automobile at rest. The speed of the automobile after 10 s will be:

Physics

1 answer:

Svetach [21]1 year ago

6 0

The speed after 10 s is 20 m/s

<h3>What is the speed after 10 s?</h3>

Given that we have the following;

force = 2800 N

Mass = 1400 kg

time = 10 s

Recall that;

F = ma

F = force

m = mass

a = acceleration

a = F/m

a = 2800 N/1400 kg

a = 2 m/s^2

Now;

v = u + at

v = ??

u = 0 m/s

a= 2 m/s^2

t = 10 s

v = at

v = 2 * 10

v = 20 m/s

Learn more about the speed:brainly.com/question/28224010

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Answer:

$2.09\ \text{m/s}$

$22298.4\ \text{J}$

Explanation:

m = Mass of each the cars = $1.6\times 10^4\ \text{kg}$

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$u_2$ = Initial velocity of the other two cars = 1.4 m/s

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As the momentum is conserved in the system we have

$mu_1+2mu_2=3mv\\\Rightarrow v=\dfrac{u_1+2u_2}{3}\\\Rightarrow v=\dfrac{3.46+2\times 1.4}{3}\\\Rightarrow v=2.09\ \text{m/s}$

Speed of the three coupled cars after the collision is $2.09\ \text{m/s}$ .

As energy in the system is conserved we have

$K=\dfrac{1}{2}mu_1^2+\dfrac{1}{2}2mu_2^2-\dfrac{1}{2}3mv^2\\\Rightarrow K=\dfrac{1}{2}\times 1.6\times 10^4\times 3.46^2+\dfrac{1}{2}\times 2\times 1.6\times 10^4\times 1.4^2-\dfrac{1}{2}\times 3\times 1.6\times 10^4\times 2.09^2\\\Rightarrow K=22298.4\ \text{J}$

The kinetic energy lost during the collision is $22298.4\ \text{J}$ .

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3 years ago

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OlgaM077 [116]

Answer:

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3 years ago

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Answer:

$Q = 8,345 * v$

Explanation:

So, we are looking for an expression of the amount of water that has been drained from the tub. The expression is in terms of v that represent the number of gallons of water drained since the plug was pulled. Since we are interested in the pounds of water that has been drained from the tub we need to take into account that for every gallon of water drained, 8.345 pounds have left the tub. Therefore, the expression for the weight of water Q that has been drained from the tub in terms of v is simply :

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3 years ago

A car travels 200km in 3.0 hours. Determine the average velocity of the car

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Answer:

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Answer:

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