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2 years ago

A net force of 2800 N is applied to a 1400 kg automobile at rest. The speed of the automobile after 10 s will be:

Physics

1 answer:

Svetach [21]2 years ago

6 0

The speed after 10 s is 20 m/s

<h3>What is the speed after 10 s?</h3>

Given that we have the following;

force = 2800 N

Mass = 1400 kg

time = 10 s

Recall that;

F = ma

F = force

m = mass

a = acceleration

a = F/m

a = 2800 N/1400 kg

a = 2 m/s^2

Now;

v = u + at

v = ??

u = 0 m/s

a= 2 m/s^2

t = 10 s

v = at

v = 2 * 10

v = 20 m/s

Learn more about the speed:brainly.com/question/28224010

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A skateboarder with a mass of 60 kg moves with a force of 20 N. What is her acceleration?

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Explanation:

Solution,

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2 years ago

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3 years ago

At a rock concert, the sound intensity 1.0 m in front of the bank of loudspeakers is 0.10 W/m². A fan is 30 m from the loudspeak

Klio2033 [76]

To solve this problem we will apply the concepts related to the Area, the power and the proportionality relationships between intensity and distance.

The expression for sound power is,

$P = AI$

Here,

A = Area

I = Intensity

P = Power

At the same time the area can be written as,

$A = \frac{\pi d^2}{4}$

Now the intensity is inversely proportional to the square of the distance from the source, then

$I \propto \frac{1}{r^2}$

The expression for the intensity at different distance is

$\frac{I_1}{I_2}= \frac{r^2_2}{r_1^2}$

Here,

$I_1$ = Intensity at distance 1

$I_2$ = Intensity at distance 2

$r_1$ = Distance 1 from light source

$r_2$ = Distance 2 from the light source

If we rearrange the expression to find the intensity at second position we have,

$I_2 = I_1 (\frac{r_1^2}{r_2^2})$

If we replace with our values at this equation we have,

$I_2 = (0.10W/m^2)(\frac{1.0m^2}{30.0m^2})$

$I_2 = 1.11*10^{-4} W/m^2$

Now using the equation to find the area we have that

$A = \frac{\pi (8.4*10^{-3}m)^2}{4}$

$A = 5.5*10^{-5}m^2$

Finally with the intensity and the area we can find the sound power, which is

$P = AI$

$P = (5.5*10^{-5}m^2)(1.11*10^{-4}W/m^2)$

$P = 6.1*10^{-9}J/s$

Power is defined as the quantity of Energy per second, then

$E = 6.1*10^{-9}J$

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4 years ago

A visible violet light emits light with a wavelength of 4.00 × 10-7 m.

RideAnS [48]

Answer:

The correct option is B. 7.5 * 10¹⁴ Hz

Explanation:

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= (0.75 x 10¹⁵) /sec

= 7.5 x 10¹⁴ Hz

= 750,000 GHz

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3 years ago

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