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OverLord2011 [107]
4 years ago
13

Which event are dependent?

Mathematics
1 answer:
expeople1 [14]4 years ago
4 0

Answer:

C, I and II

Step-by-step explanation:

Removing one paperclip or one candy from a container leaves less in the container. This raises the probability of picking a specific item from the bunch.

ex. There's 5 rocks in a box. 20% chance to pick each one. Remove one of the rocks and the percentage rises to 25%. Now there's a higher chance to pick one specific rock.

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A circle has a diameter of 25cm. How far from the centre of this circle is a chord 16cm long? Draw a picture before you start.
yan [13]

Answer:

The cord is 9.6 cm away from the centre of the circle.

Step-by-step explanation:

<u>See The Image First</u>

The image below shows a picture of everything that’s given, labeled, and drawn in the circle.

<u>Description of the Picture:</u>

You can use the Pythagorean to find the what the distance (the length <em>b</em>) the cord is from the center. You can use the radius as the hypotenuse. The radius is half of the diameter, and the diameter is 25. So the radius is 12.5, which means that 12.5 is the hypotenuse of the triangle (also known as side <em>c</em>). The whole length of the cord is 16cm long, and we can use half of the cord, which is 8cm, for the triangle. So we know two sides already: the hypotenuse (the radius) and the length <em>a</em> of the triangle (half of the length of the cord).

<u>To Solve (variables </u><em><u>a</u></em><u>, </u><em><u>b</u></em><u>, and</u><em><u> c</u></em><u>, are in italics so you don’t get confused):</u>

⇒ Use the formula of the Pythagorean Theorem (a^{2}+b^{2}=c^{2}), where <em>b </em>is the length of the distance from the cord to the centre of the circle (what we need to find out), <em>a </em>is the length of the side of the triangle (half of the cord size – 8cm), and <em>c </em>is the hypotenuse (the radius – 12.5cm). So plug the given values of <em>b</em> and <em>c</em> into the formula:

a^{2}+8^{2}=12.5^{2}

⇒ Solve for <em>a </em>by simplify:

a^{2}+64=156.25

⇒ Subtract 64 from both sides:

a^{2}=92.25

⇒ Find the square root of both sides to get<em> a</em> by itself:

\sqrt{a^{2}}=\sqrt{92.25}

⇒ Simplify to get:

a=\sqrt{92.25}  which convert’s to a=9.60468635...  round the answer to the nearest tenth is a=9.6

<u />

<u>Answer:</u> The cord is 9.6 cm away from the centre of the circle.

I hope you understand and that this helps with your question! :)

8 0
3 years ago
Equations with variables on both sides<br> 9e+4=14+8e
frozen [14]
9e + 4 = 14 + 8e
9e = 10 + 8e (Subtract 4 from both sides)
e = 10 (Subtract 8e from both sides)
6 0
3 years ago
Read 2 more answers
What is the axis of symmetry of y=x^2+4x-5
mylen [45]
X= 2 is the axis of symmetry
3 0
4 years ago
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In 2011, the world's largest pumpkin weighed 825 kilograms. An average-sized pumpkin weighs 5,000 grams. The 2011 world-record p
zzz [600]
1000 g = 1 kg
5,000 g = 5 kg
825 kg - 5 kg = 820 kg

<span>The 2011 world-record pumpkin weighs __820 kg___ kilograms more than an average-sized pumpkin. </span>
6 0
3 years ago
A boat is anchored 2.2 km due south of a lighthouse. Along the shore, the town of Beachton is 16.8 km due east of the lighthouse
Pavlova-9 [17]
Distance from the boat to the town:
d² = 2.2² + 16.8²
d² = 4.84 + 282.24
d² = 287.08
d = √287.08
d = 16.9434 ≈ 16.9 km
5 0
4 years ago
Read 2 more answers
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