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yaroslaw [1]
3 years ago
5

Achargingbullelephantwithamassof5240kgcomesdi- rectly toward you with a speed of 4.55 m/s. You toss a 0.150-kg rubber ball at th

e elephant with a speed of 7.81 m/s. (a) When the ball bounces back toward you, what is its speed? (b) How do you account for the fact that t
Physics
1 answer:
Ierofanga [76]3 years ago
8 0

Answer:

Given:

Mass of elephant = 5240 kg

The initial speed of the elephant = 4.55 m/s

Mass of the rubber ball, m, = 0.15 kg

Inital speed of the rubber ball, v = 7.81 m/s

On substitution  in V_{2f} = [\frac{2m_{1} }{m_{1} +m_{2} } ]V_{1f} + [\frac{m_{2}-m_{1}}{m_{1}+m_{2}  } ] v_{2f}

V_{2f} = [\frac{2*5240_{} }{5240_{} +0.15_{} } ](-4.55_{}) + [\frac{0.15_{}-5240_{}}{5240_{}+0.15_{}  } ] (7.81_{})

a) The negatıve sign shows that the ball bounces back in the direction opposite  to the incident

b)  it is clear that the velocity of the ball increases and therefore it is kinetic energy . The ball gains kinetic energy from the elephant.

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Answer:

when the radius is halved, F becomes 4 times

Explanation:

<u><em>The formula is given by</em></u>

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<u><em>When r is halved:</em></u>

F = \frac{Gm1m2}{(1/2r)^2}

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Answer:

A. Technician A only.B.

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4 years ago
Officials begin to release water from a full man-made lake at a rate that would empty the lake in 4 weeks, but a river that can
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Answer:

5 weeks and 5 days is required to empty the lake

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Officials begin the remove water from a full man made lake

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= -1/4

A river can fill the lake up in 15 weeks

= 1/15

Let t represent the number of weeks that is required to empty the lake

= -1/t

Therefore the number of weeks it takes to empty the lake can be calculated as follows

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-1/t= -11/60

Cross multiply

-11×t= -1×60

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The magnitude of their combined

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Substitute all the parameters into the formula

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Therefore, the magnitude of their combined momentum before the crash will be 20 kgm/s

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