Question

A Carnot engine operates with a cold reservoir at a temperature of 455 K and a hot reservoir at a temperature of 619 K. What is the net entropy change (in J/K) as it goes through a complete cycle? Round your answer to the nearest whole number.

Answer 1

Answer:

Assuming that 4000 J of heat transfer occurs from it the change in entropy will be=2.33j/k

Explanation:

Given data

Th=619 K

Tc= 455K

We are going to assume that 4000 J of heat transfer occurs from it, since it was not specified in the question.

we know that the change in entropy is given as

ΔStotal=ΔShot+ΔScold .

ΔShot=−Q/Th=−4000J/619K=−6.46J/K

For the cold reservoir,

ΔScold=Q/Tc=4000J/455K=8.79J/K

therefore  the total is

ΔStotal=ΔShot+ΔScold

=(−6.46+8.79)J/K

=2.33j/k