The momentum of a neutron p = 586.25 kg m / s.
<u>Explanation:</u>
The product of mass and the velocity gives the momentum of an object and it is a vector quantity. It is denoted by the letter p. The unit of momentum is kilogram meter per second (or) kg m / s.
Given mass m = 1.675 
10, velocity v = 3.500 10
Momentum, p = mv
where m represents the mass,
v represents the velocity.
momentum p = (1.675 10) (3.500 10)
momentum p = 586.25 kg m / s.
Answer:
Explanation:This question is simply asking you to describe the following equations:
E = hv
v = c/L
E = hc/L
where E is the energy, h is Planck's constant, v is the frequency, c is the speed of light and L is the wavelength.
By looking at the equations you should be able to tell what the relationships between energy, frequency and wavelength are. If you are having difficulty describing them, then create a table with actual values and see what happens to the energy as you increase or decrease the frequency and/or wavelength.
A; Metal This is because of maths
Answer:
E. An object’s velocity changes at a constant rate, and its acceleration remains constant.
Explanation:
When an object is in freefall, it implies that the object is falling freely under gravity. If it falls towards the earth surface, the fall is in the direction of the Earth's gravitational force.
At the point of release of the object, its initial velocity is zero because it is at rest. But when released, its velocity increases at a constant rate until it is acted upon by an external force. But its acceleration remains constant, acceleration due to gravity.
Answer:
P = 7.28 N.s
Explanation:
given,
initial momentum of cue ball in x- direction,P₁ = 9 N.s
momentum of nine ball in x- direction, P₂ = 2 N.s
momentum in perpendicular direction i.e. y - direction,P'₂ = 2 N.s
momentum of the cue after collision = ?
using conservation of momentum
in x- direction
P₁ + p = x + P₂
p is the initial momentum of the nine balls which is equal to zero.
9 + 0 = x + 2
x = 7 N.s
momentum in x-direction.
equating along y-direction
P'₁ + p = y + P'₂
0 + 0 = y + 2
y = -2 N.s
the momentum of the cue ball after collision is equal to resultant of the momentum .
P = 7.28 N.s
the momentum of the cue ball after collision is equal to P = 7.28 N.s
