Answer:
C. 28.09 amu
Explanation:
The natural occurring element exist in 3 isotopic forms: namely X-28 (27.977 amu, 92.23% abundance), X-29 (28.976 amu, 4.67% abundance) and X-30 (29.974 amu, 3.10% abundance).
The atomic weight of elements depends on the isotopic abundance. If you know the fractional abundance and the mass of the isotopes the atomic weight can be computed.
The atomic weight is computed as follows:
atomic weight = mass of X-28 × fractional abundance + mass of X-29 × fractional abundance + mass of X-30 × fractional abundance
atomic weight = 27.977 × 0.9223 + 28.976 × 0.0467 + 29.974 × 0.0310
atomic weight = 25.8031871 + 1.3531792 + 0.929194
atomic weight = 28.0855603 amu
To 2 decimal place atomic weight = 28.09 amu
Answer:
Distance traveled during this acceleration will be 6950 m
Explanation:
Wear have given maximum speed tat will be equal to final speed of the car v = 278 m/sec
Constant acceleration 
As the car starts initially starts from rest so initial velocity of the car u = 0 m/sec
From third equation of motion 
Putting all values in equation
s = 6950 m
So distance traveled during this acceleration will be 6950 m
Answer:
soil additive
Explanation:
Soil Additive
The three main components of humus are fulvic acid, humic acid and humin. The spongy nature of humus helps it to trap and hold water, this particular property also helps to aerate the soil as humus expands and contracts with available water.
A elephant kicks a 5.0\,\text {kg}5.0kg5, point, 0, start text, k, g, end text stone with 150\,\text J150J150, start text, J, en
S_A_V [24]
The speed of the stone is 7.7 m/s
Explanation:
The kinetic energy of a body is the energy possessed by the body due to its motion. Mathematically,
where
m is the mass of the body
v is its speed
For the stone in this problem, we have:
K = 150 J is its kinetic energy
m = 5.0 kg is its mass
Re-arranging the equation for v, we find the speed of the stone:
Learn more about kinetic energy:
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