Answer:
As each mower presumably needs the same torque to start, and torque is a product of force and moment arm, the longer moment arm of 10.42 cm on Uwi's mower means lower force is required when compared to Urippe's shorter moment arm of 1.35 cm
350 rev/min = 350(2π) / 60 = 36.652 rad/s
36.652 rad/s / 0.294 s = 124.66... <u>125 rad/s²</u>
a = αR = 125(0.1042) = 12.990... <u>13 m/s²</u>
a = αR = 125(0.0135) = 1.68299... <u>1.7 m/s²</u>
I am GUESSING that we are supposed to model these mowers as a uniform disk
τ = Iα
FR = (½mr²)α
F = mr²α/2R
Urippe's pull = (3.56)(0.2041²)(124.66) / (2(0.0135)) = 702.008... <u>702 N</u>
Usi's pull = (3.56)(0.2041²)(124.66) / (2(0.1042)) = 90.9511...<u>91.0 N</u>
L = Iω = (½(3.56)(0.2041²))36.652 = 2.71771...<u>2.72 kg•m²/s down</u>
using the right hand rule
Answer:
OPTION D (The waves will sometimes get very high and very low) is the answer.
Explanation:
Wavelength = velocity ÷ frequency
As the frequency which measures the number of waves per unit of time is inversely proportional to the wavelength, point X which lies between two sources, and one source is shorter than another, the wave heights at point x will vary as the distances from point X vary too. This means that waves at point X depending on the wave type and source will get very high at times and very low.
Explanation:
It is given that,
Speed of the sports car, v = 85 mph = 37.99 m/s
The radius of curvature, r = 525 m
Let 
is the normal weight and 
is the apparent weight of the person. Its apparent weight is given by :
So, 
or
Hence, this is the required solution.
Answer:
T
beacuse:
Energy can be transferred from one object to another by doing work. ... When work is done, energy is transferred from the agent to the object, which results in a change in the object's motion (more specifically, a change in the object's kinetic energy).
Answer:
K = -½U
Explanation:
From Newton's law of gravitation, the formula for gravitational potential energy is;
U = -GMm/R
Where,
G is gravitational constant
M and m are the two masses exerting the forces
R is the distance between the two objects
Now, in the question, we are given that kinetic energy is;
K = GMm/2R
Re-rranging, we have;
K = ½(GMm/R)
Comparing the equation of kinetic energy to that of potential energy, we can derive that gravitational kinetic energy can be expressed in terms of potential energy as;
K = -½U
