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ASHA 777 [7]
3 years ago
11

I NEED THIS ASAP TODAY PLEASSSSEEEEEE

Chemistry
1 answer:
alukav5142 [94]3 years ago
7 0

Option C, mass would be same. Only the gravitational pull will be different

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How does the mass of an electron compare to the mass of a proton and a
tensa zangetsu [6.8K]

Answer:

C. The mass of an electron is much less than the mass of a proton or

a neutron.

Explanation:

When we compare the mass of an electron to that of proton or neutron, the mass of an electron is much less than the mass of a proton or a neutron.

Electrons are negatively charged particles in an atom

Protons are positively charged particles

Neutrons do not carry any charges.

  • The relative mass of an electron compared to that of a proton is \frac{1}{1840}
  • This is a very small value
  • Electrons generally have mass of 9.11 x 10⁻³¹kg
  • Protons weigh 1.67 x 10⁻²⁷kg
  • Neutrons weigh  1.68 x 10⁻²⁷kg

We can see that electrons have very small mass and this is why when calculating the mass of an atom, we use the sum of the number of protons and neutrons.

6 0
3 years ago
PLEASE HELP it would be really nice of you to answer this question i would be very grateful <3
Aleksandr-060686 [28]

Answer: D (The abundance percentage of each isotope)

Explanation: hope this helps!

7 0
3 years ago
Read 2 more answers
You measure salt water in a tank to have a density of 1.02 g/mL. A balloon weighs 2.0 g and you weights have a mass of 30.0 g ea
Elden [556K]

Weight of the balloon = 2.0 g

Six weights each of mass 30.0 g is added to the balloon.

Total mass of the balloon = 2.0 g + 6*30.0 g = 182 g

Density of salt water = 1.02 g/mL

Calculating the volume from mass and density:

182g*\frac{mL}{1.02g} =178mL

Converting the volume from mL to cubic cm:

178 mL * \frac{1cm^{3} }{1mL} =178cm^{3}

Assuming the balloon to be a sphere,

Volume of the sphere = \frac{4}{3}πr^{3}

178 cm^{3} = \frac{4}{3}(\frac{22}{7})r^{3}

r = 3.49 cm

Radius of the balloon = 3.49 cm

Diameter of the balloon = 2 r = 2*3.49 cm = 6.98cm


4 0
3 years ago
HELP PLEASE I WILL GIVE 100 PONTS
pochemuha

Answer:

boiling point

Explanation:

5 0
3 years ago
Read 2 more answers
Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reaction:P4(g) + 10 Cl2(g) → 4PCl5(s) ΔH°
miskamm [114]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -1835 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

P_4(g)+10Cl_2(g)\rightarrow 4PCl_5(s)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) PCl_5(s)\rightarrow PCl_3(g)+Cl_2(g)    \Delta H_1=157kJ   ( × 4)

(2) P_4(g)+6Cl_2(g)\rightarrow 4PCl_3(g)     \Delta H_2=-1207kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[4\times (-\Delta H_1)]+[1\times \Delta H_2]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(4\times (-157))+(1\times (-1207))=-1835kJ

Hence, the \Delta H^o_{rxn} for the reaction is -1835 kJ.

6 0
3 years ago
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