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melomori [17]
3 years ago
6

Calculate the number of molecules in 100. g of O2 *

Chemistry
1 answer:
Sindrei [870]3 years ago
6 0
I am pretty sure the answer is 6.25 molecules
See picture for explanation
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The mass of an unidentified metal sphere is 133 grams. Students determine the
Rainbow [258]

Given the data from the question, the identity of the unknown metal having a of mass 133 g is Cobalt

<h3>What is density? </h3>

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

<h3>How to determine the density </h3>
  • Mass = 133 g
  • Volume of water = 25 mL
  • Volume of water + metal = 40 mL
  • Vol of metal = 40 – 25 = 15 mL
  • Density =?

Density = mass / volume

Density = 133 / 15

Density = 8.86 g/mL

Comparing the density of the unknown metal (i.e 8.86 g/mL) with those given in the chart in the question above, we can conclude that the unknown metal is Cobalt

Learn more about density:

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2 years ago
You are planning an investigation that explores properties of matter.
Elena-2011 [213]

Answer:

Placing a powder into a beaker that contains liquid, resulting the beaker to get hotter.

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Physical property is something that you can observe that does not affect the mixture/solution/substance, and that includes temperature

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2 years ago
If a car is traveling 100 km/h and comes to a stop in 3 minutes,what is acceleration of a passenger who is using vehicle restrai
Rama09 [41]

We are given –

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Here–

\qquad\pink{\bf \longrightarrow  Initial\:  velocity =  100 \:km/hr}

\qquad\sf \longrightarrow  Initial\:  velocity = \dfrac{ 100 \times 1000}{3600} \:m/s

\qquad\pink{ \bf \longrightarrow  Initial\:  velocity = 27.78\: m/s}

Now –

\qquad____________________________

\qquad\purple{\bf \longrightarrow  Acceleration  = \dfrac{Final\: Velocity -Initial  \:Velocity }{Time}}

\qquad\purple{\bf \longrightarrow  Acceleration  = \dfrac{v -u}{t}}

\qquad\sf \longrightarrow  Acceleration = \dfrac{(0- 27.78)}{1800}

\qquad\sf \longrightarrow  Acceleration =\cancel{ \dfrac{- 27.78}{1800}}

\qquad\purple{\bf \longrightarrow  Acceleration = -0.15 \: m/s^2}

\qquad_______________________________

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2 years ago
The stronger the wind, the larger the particles it erodes.
Fittoniya [83]
I believe the statement above is true. The stronger the wind, the larger the particles it erodes<span>. The stronger the wind, the larger the particles that are carried away.

</span>
7 0
3 years ago
A neutral atom has the following electron configuration: What is the chemical symbol for the atom? How many electrons does the a
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Answer:

pls the image didn't come

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