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melomori [17]
3 years ago
6

Calculate the number of molecules in 100. g of O2 *

Chemistry
1 answer:
Sindrei [870]3 years ago
6 0
I am pretty sure the answer is 6.25 molecules
See picture for explanation
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It takes 338. kJ/mom to break a carbon-chlorine single bond. Calculate the maximum wavelength of light for which a carbon-chlori
Vesnalui [34]

Answer: The maximum wavelength of light for which a carbon-chlorine Single bond could be broken by absorbing a single photon is 354 nm

Explanation:

The relation between energy and wavelength of light is given by Planck's equation, which is:

E=\frac{Nhc}{\lambda}

where,

E = energy of the light  = 338kJ=338000J    (1kJ=1000J)

N= avogadro's number

h = Planck's constant

c = speed of light

\lambda = wavelength of light

338\times 1000J=\frac{6.023\times 10^{23}\times 6.6\times 10^{-34}\times 3\times 10^{8}}{\lambda}    

{\lambda}=0.354\times 10^{-6}m=354nm     (1nm=10^{-9}m

Thus the maximum wavelength is 354 nm

6 0
3 years ago
A substance has a volume of 20mL and a density of 2.5 g/mL. what is it’s mass?
DochEvi [55]
2.5X20=50g
50g should be the right answer
Mass=volumeXdenisty.
4 0
3 years ago
What do cyanobacteria use to produce energy and by what process do they produce energy
andrezito [222]
As they contain, green pigement they can perform "Photosynthesis" and obtains energy from that process

Hope this helps!
7 0
2 years ago
Name the noble gas atom that has the same electron configuration as each ion in the compound rubidium oxide
Zepler [3.9K]
In rubidium oxide - Rb₂O , the ions are Rb⁺ and O²⁻
Rb is a group one element with one valence electron. To become stable it loses its outer electron to gain a complete outer shell.
Electronic configuration of Rb is - 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 5s¹
Once it loses its valence electron the configuration is;
 - 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 
The noble gas with this configuration is Krypton - Kr

Oxygen electron configuration is 1s² 2s² 2p⁴
Once it gains 2 electrons the configuration is  - 1s² 2s² 3p⁶
The noble gas with this configuration is Neon - Ne
3 0
3 years ago
1. a.) Calculate the wavelength of light which has a frequency of 5.25 x 10 14 Hz.
Scilla [17]
<h3>Answer:</h3>

5.71 × 10² nm

<h3>Explanation:</h3>

The product of wavelength and frequency of a wave gives the speed of the wave.

Therefore;

Velocity of wave = Wavelength × Frequency

c = f ×λ

In our case;

Frequency = 5.25 × 10^14 Hz

Speed of light = 2.998 × 10^8m/s

But;

λ = c ÷ f

  = 2.998 × 10^8m/s ÷  5.25 × 10^14 Hz

  = 5.71 × 10^-7 m

But; 1 M = 10^9 nm

Therefore;

wavelength = 5.71 × 10^-7 × 10^9

                  = 5.71 × 10² nm

The wavelength of light wave 5.71 × 10² nm

3 0
3 years ago
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