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3 years ago

Do ionic or covalent substances tend to produce more ions in solution? ...?

2 answers:

8 0

The answer for the given question above is IONIC. Ionic substances form giant ionic lattices containing oppositely charged ions. They have high melting and boiling points, and conduct electricity when melted or dissolved in water.

Gelneren [198K]3 years ago

6 0

the answer is A. ionic

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The lower the ph of a solution, the ______.

gtnhenbr [62]

B

a and c are unrelated
d: ph will increase

3 0

3 years ago

Read 2 more answers

For the chemical reaction CaI2+2AgNO3-> 2AgI+Ca(NO3)2 how many moles of silver iodide will be produced from 205g of calcium i

Colt1911 [192]

Answer:

Moles of silver iodide produced = 1.4 mol

Explanation:

Given data:

Mass of calcium iodide = 205 g

Moles of silver iodide produced = ?

Solution:

Chemical equation:

CaI₂ + 2AgNO₃ → 2AgI + Ca(NO₃)₂

Number of moles calcium iodide:

Number of moles = mass/ molar mass

Number of moles = 205 g/ 293.887 g/mol

Number of moles = 0.7 mol

Now we will compare the moles of calcium iodide with silver iodide.

CaI₂ : AgI

1 : 2

0.7 : 2×0.7 = 1.4

Thus 1.4 moles of silver iodide will be formed from 205 g of calcium iodide.

6 0

3 years ago

Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calcu

stealth61 [152]

Answer:

Explanation:

Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calculate the value of the rate constant at 25 °C. Alternatively, you can simply extrapolate the straight line plot of ln(k) vs. 1/T in your notebook to 1/298 , read off the value of ln(k), and determine the value of k. Please put your answer in scientific notation. slope=-12070, Ea=100kJ/mol, k= 0.000717(45C), 0.00284(55C), 0.00492(65C), 0.0165(75C), 0.0396(85C)

Explanation;

According to Arrhenius equation:

i.e. ln(k2/k1) = -Ea/R (1/T2 - 1/T1)

Where, k1 = 0.000717, T1 = 45 oC = (45+273) K = 318 K

T2 = 25 oC = (25 + 273) K = 298 K

i.e. ln(k2/0.000717) = -12070 (1/298 - 1/318)

i.e. ln(k2/0.000717) = -2.54738

i.e. k2/0.000717 = $e^{-2.54738}$

= 0.078286

Therefore, the required constant (k2) = 0.078286 * 0.000717 = $5.61*10^-^5$

6 0

3 years ago

The reaction is run at two temperatures where temperature 1 is lower than temperature 2. Which relationship is correct for eithe

Tasya [4]

Answer:

The answer is " $K_1 < K_2$ "

Explanation:

In the given question, the value of the $K=Ae^{-\frac{Ea}{RT}}$ and the $T_1$ is the rate value which is the constant that is $K_2>K_1$ . As per the temperature value when its increase rate is constantly increasing. $E_a$ is activation energy it is not dependent on the temperature that why the answer is $K_1 < K_2$ .