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charle [14.2K]
3 years ago
15

The reaction of aluminum with bromine is shown here. The equation for the reaction is

Chemistry
1 answer:
m_a_m_a [10]3 years ago
5 0
Answer is (b)

2,3,1 is the stoichiometry

The values in front of the elements are the stoichiometric values
(Since Al2Br6 has no value in front, it's considered 1)
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Everything is made of molecules so I don’t think there would be life without molecules..
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3 years ago
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The atomic mass of Gallium is 69.72 AMU. The masses of the naturally occurring isotopes are 68.9257 AMU and 70.908 AMU for Ga-69
Mashcka [7]

Answer:

40.7% abundance of Ga-71

59.93% abundance of  Ga-69

Explanation:

Given data:

Average atomic mass of Ga = 69.72 amu

Atomic mass of Ga-69 = 68.9257 amu

Atomic mass of Ga-71 = 70.908 amu

Percent abundance of each isotope = ?

Solution;

we know there are two naturally occurring isotopes of Ga.

First of all we will set the fraction for both isotopes

X for the isotopes having mass 68.9257

1-x for isotopes having mass 70.908

we will use the following equation,

68.9257x +  70.908 (1-x) = 69.72

68.9257x +70.908 - 70.908x = 69.72

68.9257x -  70.908x = 69.72 - 70.908

-1.9823x =  - 1.188

x=  1.188/1.9823

x= 0.5993

0.5993 × 100 = 59.93 %

59.93 %  is abundance of Ga-69 because we solve the fraction x.

now we will calculate the abundance of Ga-71.

(1-x)

1 - 0.5993 = 0.4007

0.4007× 100= 40.7 %

40.7 % for Ga-71.

3 0
3 years ago
Determine the percentage of carbon and hydrogen in ethane C2H6 if the molecular weight is 30.
Naddika [18.5K]

Answer:

Percentage of carbon:

{ \tt{ =  \frac{24}{30}  \times 100\%}} \\  = 80\%

Percentage of hydrogen:

{ \tt{ =  \frac{6}{30}  \times 100\%} } \\  = 20\%

8 0
3 years ago
The reason that elements in the same group all have similar chemical properties is because they all have the same
sveta [45]
D-number of electrons in the outer energy level.
4 0
3 years ago
What is the volume of 2 mol of chlorine gas at STP?<br> 2.0 L<br> 11.2 L<br> 22.4 L<br> 44.8 L
nirvana33 [79]

Answer:

44.8 L

Explanation:

Using the ideal gas law equation:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

At Standard temperature and pressure (STP);

P = 1 atm

T = 273K

Hence, when n = 2moles, the volume of the gas is:

Using PV = nRT

1 × V = 2 × 0.0821 × 273

V = 44.83

V = 44.8 L

7 0
2 years ago
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