All categories

3 years ago

Write down a transfer function of a stable system for which pure proportional feedback could drive the system unstable.

Engineering

1 answer:

gtnhenbr [62]3 years ago

6 0

Answer:

$Gs = 1 / (s + 1)^3$

Explanation:

A system is known to be a stable system if the poles of the system lie on the negative real axis of the s plane.

A system that could be driven unstable by a P-controller would be:

$Gs = 1 / (s + 1)^3$

As the value of K increases, the closed loop poles move into the right half s plane

You might be interested in

Burn rate can be affected by: A. Variations in chamber pressure B. Variations in initial grain temperature C. Gas flow velocity

Digiron [165]

Answer: D) All of the above

Explanation:

Burn rate can be affected by all of the above reasons as, variation in chamber pressure because the pressure are dependence on the burn rate and temperature variation in initial gain can affect the rate of the chemical reactions and initial gain in the temperature increased the burning rate. As, gas flow velocity also influenced to increasing the burn rate as it flowing parallel to the surface burning. Burn rate is also known as erosive burning because of the variation in flow velocity and chamber pressure.

4 0

3 years ago

Brainly and points if you want

Tju [1.3M]

Answer:

thank you

Explanation:

have a nice day

8 0

3 years ago

Read 2 more answers

10% A steel beam W18x76 spans 32 feet and is subjected to a Moment of 334 kips-ft. Find the load w on the beam. Determine the de

Lilit [14]

Answer:

w = 10.437 kips

deflection at 1/4 span 20.83\E ft

at mid span = 1.23\E ft

shear stress 7.3629 psi

Explanation:

area of cross section = 18*76

length of span = 32 ft

moment = 334 kips-ft

we know that

moment = load *eccentricity

334 = w * 32

w = 10.437 kips

deflection at 1/4 span

$\delta = \frac{wa^2b^2}{3EI}$

$= \frac{10.4375*8^2 *24^2}{3E \frac{BD^3}{12}}$

$=\frac{10.437 *8^2*24^2}{3E \frac{18*16^3}{12}}$

= 20.83\E ft

at mid span

$\delta = \frac{wl^3}{48EI}$

$= \frac{10.43 *32^3}{48 *E*\frac{18*16^3}{12}}$

$\delta = 1.23\E ft$

shear stress

$\tau = \frac{w}{A} = \frac{10.43 7*10^3}{18*76} =7.3629 psi$

6 0

3 years ago

Locate the centroid y¯ of the composite area. Express your answer to three significant figures and include the appropriate units

german

Answer:

Please see the attached Picture for the complete answer.

Explanation:

4 0

3 years ago

What is the instantaneous center of zero velocity? List two approaches for determining the is the instantaneous center of zero v

Lera25 [3.4K]

Explanation:

Instantaneous center:

It is the center about a body moves in planer motion.The velocity of Instantaneous center is zero and Instantaneous center can be lie out side or inside the body.About this center every particle of a body rotates.

From the diagram

Where these two lines will cut then it will the I-Center.Point A and B is moving perpendicular to the point I.

If we take three link link1,link2 and link3 then I center of these three link will be in one straight line It means that they will be co-linear.

$I_{12},I_{23},I_{31} all\ are\ co-linear.$

5 0

3 years ago