A 3 ft x 2 ft block moves down a 15 degree inclined slope at a speed of V = 0.2 ft/s over a thin layer (h = 0.0125 ft) of oil wi
th a dynamic viscosity of 8.2 x 10^-2 lbf-s/ft^2. What is the weight of the block? Draw FBD.
1 answer:
Answer:
mg = 30.415 lbf
Explanation:
from figure body of size 3ft*2ft is tend to move down side
weight is divided into two component
vertical component = mgcos15 and
horizontal component = mg sin15
considering horizontal component equal to shear force
mgsin15 = \tau A
mgsin15 =\mu \frac{dv}{dh} A
mg =\frac{ \mu v A}{h*sin15}
=\frac{8.2*10^{-2}*0.2*3*2}{0.0125*sin15}
mg = 30.415 lbf
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Answer:
The specific volume is reduced in 80 per cent due to isothermal compression.
Specific enthalpy remains constant.
Explanation:
Let suppose that neon behaves ideally, the equation of state for ideal gases is:
Where:
- Pressure, measured in kilopascals.
- Volume, measured in cubic meters.
- Molar quantity, measured in kilomoles,
- Temperature, measured in kelvins.
- Ideal gas constant, measured in
.
On the other hand, the molar quantity () and specific volume (
), measured in cubic meter per kilogram, are defined as:
and
Where:
- Mass of neon, measured in kilograms.
- Molar mass of neon, measured in kilograms per kilomoles.
After replacing in the equation of state, the resulting expression is therefore simplified in term of specific volume:
Since the neon is compressed isothermally, the following relation is constructed herein:
Where:
,
- Initial and final pressure, measured in kilopascals.
,
- Initial and final specific volume, measured in cubic meters per kilogram.
The change in specific volume is given by the following expression:
Given that and
, the change in specific volume is:
The specific volume is reduced in 80 per cent due to isothermal compression.
Under the ideal gas supposition, specific enthalpy is only function of temperature, as neon experiments an isothermal process, temperature remains constant and, hence, there is no change in specific enthalpy.
Specific enthalpy remains constant.
Answer:
Explanation:
The answer to the above question is given in attached files.
