The ratio of the distance moved by the point at which the effort is applied in a simple machine to the distance moved by the point at which the load is applied, in the same time. In the case of an ideal (frictionless and weightless) machine, velocity ratio = mechanical advantage. Velocity ratio is sometimes called distance ratio.
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Answer:
a.) 490m
b.) 98m/s
Explanation:
Given that the
Acceleration g = 9.8 m/s^2
Time = 10s
Since the parachutist jumps out of an aeroplane. The parachutist jumped out from rest. Initial velocity U is therefore equal to zero. That is,
U = 0
Distance covered = height H
The height can be calculated by using second equation of motion
H = Ut + 1/2gt^2
Substitute g and t into the formula
H = 1/2 × 9.8 × 10^2
H = 490 m
Therefore, she travels as far as 490 m
b.) Her final velocity can be calculated by using third equation of motion
V^2 = U^2 + 2gH
Substitute g and H into the formula.
Remember that U = 0
V^2 = 2 × 9.8 × 490
V^2 = 9604
V = sqrt (9604)
V = 98 m/s
Therefore, her final velocity is 98 m/s
Answer:
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