A 0.260 m radius, 525 turn coil is rotated one-fourth of a revolution in 4.17 ms, originally having its plane perpendicular to a
1 answer:
Answer:
B = 0.37T
Explanation:
In order to calculate the needed magnitude of the magnetic force you use the following formula, which calculate the induced emf of the solenoid when there is a change in the magnetic flux:
(1)
emf: induced voltage in the solenoid = 10,000V
N: turns of the solenoid = 525
ФB: magnetic flux
B: magnitude of the magnetic field = ?
A: cross-sectional area of the solenoid = π*r^2
r: radius of the cross-sectional area = 0.260m
Δt: interval time of the change of the magnetic flux = 4.17ms = 4.17*10^-3s
First, you have the magnetic field direction perpendicular to the plane of the solenoid, after, the angle between them is 90° (quarter of a revolution)
In the equation (1) the only parameter that changes on time is the angle, then, you can solve for B from the equation (1):
Finally, you replace the values of the parameters to calculate B:
The strength of the magnetic field is 0.37T
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