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damaskus [11]
3 years ago
9

Answers fast please. 1.) y=x−63x+2y=8 Use the substitution method. A.) (4, −2) B.) (14, 8) C.) (0, −6) D.) (3, −3) 2.) What is t

he x-coordinate of the solution for the system of equations? {y−x=910+2x=−2y X= what? 3.) What is the y-coordinate of the solution for the system of equations? {y=3x−1x−y=−9 Y=what?
Mathematics
2 answers:
Helga [31]3 years ago
6 0
1.
<span>A.) (4, −2)

2.
x = -7
y = 2

3.
x = 5
y = 14</span>
GrogVix [38]3 years ago
4 0

<u>QUESTION 1</u>

The given system of equation is

y=x-6...eqn1

and


3x+2y=8...eqn2


Let us substitute equation (1) into equation (2) to get,

3x+2(x-6)=8


We expand the bracket to get,

3x+2x-12=8


We simplify to get.

5x-12=8


We group like terms to get

5x=8+12

\Rightarrow 5x=20

\Rightarrow x=4


We now substitute x=4 in to equation (1) to obtain,


y=4-6=-2


The correct answer is option A.


<u>QUESTION 2</u>

The given system of equations is

y-x=9...eqn1


and

10+2x=-2y...eqn2

We make y the subject in equation (2) to get,

y=-x-5..eqn3


We put equation (3) into equation (1) to obtain,


-x-5-x=9


We group like terms to get,

-x-x=9+5


This implies that,

-2x=14


We divide through by -2 to get,

x=-7


Hence the x-coordinate is -7



<u>QUESTION 3</u>

The given system is

y=3x-1..eqn1


and


x-y=-9...eqn2

We make x the subject in equation (2) to get,

x=y-9...eqn3


We put equation (3) into equation (1) to obtain,


y=3(y-9)-1


We expand the bracket to get,


y=3y-27-1


Group like terms to get,


y-3y=-27-1


We simplify to get;

-2y=-28


This implies that,

y=14


Therefore the y-coordinate is 14.

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