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andrey2020 [161]
3 years ago
9

Simplify (6ab3c)(-abc2). a-6a2b4c3 b-6ab3c2 c-6b2c

Mathematics
1 answer:
Misha Larkins [42]3 years ago
6 0
<span>(6ab</span>³<span>c)(-abc</span>²<span>) = -6a</span>²b⁴c³
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What is the ratio of the number of cups of apple juice to the number of cups of lemon-lime soda?
viktelen [127]
It has a 6:1 ratio meaning for every 6 cups of apple juice there is 1 cup of lemon-lime soda
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3 years ago
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Find the surface area of the cube shown.<br> (_________) square centimeters
Step2247 [10]

Answer:

The answer is: 181.5 square centimeters.

Step-by-step explanation:

The cube has six faces, and each face is a square with sides of length 5.5, so the area of one of this faces is 5.5^2=30.25, adding the six faces, we get the answer: A=6\times 30.25=181.5

5 0
3 years ago
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How to solve and answer please.
jek_recluse [69]

Answer:

sin 77°

cos 49°

tan 22°

Step-by-step explanation:

use your calculator with trig functions to find the arcsin, arccos, and arctan

7 0
2 years ago
An article in Fire Technology investigated two different foam-expanding agents that can be used in the nozzles of firefighting s
UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

X[bar]₁= 4.7

S₁= 0.6

Sample 2 (alcohol-type concentrates )

n₂= 5

X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= \frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }

a) 95% CI

(X[bar]_1 - X[bar]_2) ± t_{n_1 + n_2 - 2}*Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }

Sa²= \frac{(n_1-1)S_1^2 + (n_2-1)S_2^2}{n_1 + n_2 - 2}= \frac{(5-1)0.36 + (5-1)0.64}{5 + 5 - 2}= 0.5

Sa= 0.707ç

t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306

(4.7-6.9) ± 2.306* (0.707\sqrt{\frac{1}{5}+\frac{1}{5} })

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

b.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

8 0
3 years ago
It says to classify what does this mean I be dumb
Alex787 [66]

for 10 x = 28.

8x-44=180
+44. +44

8x=224

224/8=28
7 0
3 years ago
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