F=\dfrac{9}{5}C+32\\\\A.\\\dfrac{9}{5}C+32=F\ \ \ |-32\\\\\dfrac{9}{5}C=F-32\ \ \ |\cdot\dfrac{5}{9}\\\\C=\dfrac{5}{9}(F-32)
B.\\F=212\to C=\dfrac{5}{9}(212-32)=\dfrac{5}{9}\cdot180=100\\\\212^oF=100^oC
C.\\F=80\to C=\dfrac{5}{9}(80-32)=\dfrac{5}{9}\cdot48\approx26.7\\\\80^oF\approx26.7^oC
Answer:
Helllllp
Step-by-step explanation:
Answer:
height = 12 cm
Step-by-step explanation:
Parallelogram 1:
Area = base *height = 20 * 15 = 300 sq. cm
Area of parallelogram 2 = area of parallelogram 1
25 * height = 300
height = 300/25
height = 12 cm
X=4
This is because
(4)3-2=10
12-2=10
10=10
This makes the statement true!
Hope this helps have a good day!
Answer:
The perimeter of the dog's play area is 30 ft
Step-by-step explanation:
Rectangle:
- The opposite sides are congruent.
- The opposite angles are congruent.
- The sum of all four angles of a rectangle is 360°.
- The sum of two adjacent angles of a rectangle is 180°.
- The diagonals bisect each other.
- The perimeter of a rectangle is = 2(Length+width)
- The area of a rectangle is = Length × width
Given that,
The length of the long side of the dog's play area was = 10 ft.
So, Length of dog's play area is = 10 ft.
The length of the short side of the dog's play area was = 5 ft.
So, width of dog's play area is = 5 ft.
It is a rectangular plot.
So, the perimeter of the dog's play area is =2(Length+width)
=2(10+5) ft
=2(15) ft
=30 ft
