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Kitty [74]
3 years ago
5

Prove that, s=u+v/2please I need help ​

Physics
1 answer:
Hoochie [10]3 years ago
5 0

Answer:

Actually the formulae is S=(u+v/2)t

.TO explain,from average velocity=distance /time

and average velocity is u+v/2

hence using the formular

Average velocity=distance/time

distance will be=average velocity ×time

so S=(u+v/2)t

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How is the current controlled for a given voltage
Leni [432]

Answer:

The current can be controlled by modifying the resistance value

Explanation:

The current can be controlled by modifying the resistance value, usually a variable resistance device called potentiometer is used. This can be observed mathematically using the ohm law which is defined as voltage equal to the current product by resistance.

V = I*R

where:

I = current [amp]

R = resistance [ohm]

V = voltage [volt]

We can see that if we reduce the resistance the current will be increased

I = v / R

And if we amplify the resistance (R) the current will be diminished

6 0
4 years ago
You are out and about in the country and your father sees a rock that he really wants in the yard. Now you must get the very hea
kupik [55]

Answer:

the 8 feet long plank has the most mechanical advantage

Explanation:

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3 years ago
Two immersion heaters, A and B, are both connected to a 120.0-V supply. Heater A can raise the temperature of 1.00 L of water fr
Inessa05 [86]

Answer:

Ratio of resistance of heater A to resistance of heater B is 5.80

Explanation:

Consider C be the specific heat of water, R₁ and R₂ be the resistance of heater A and heater B respectively.

Given:

Mass of water in heater A, m₁ = 1 L

Mass of water in heater B, m₂ = 5.80 L

Initial temperature, T₀ = 20 ⁰C

Final temperature, T₁ = 90 ⁰C

Time, t = 5 min

Amount of heat required to raise the temperature of water by heaters A and B are given by:

Q₁ = m₁C(T₁ - T₀)       and  

Q₂ = m₂C(T₁ - T₀)

Ratio of power used by both the heaters A and B is:

\frac{P_{1} }{P_{2} } =\frac{Q_{1} }{t} \times\frac{t}{Q_{2} }

Since, time t, temperature difference(T₁ - T₀) and specific heat C are same for both the heaters A and B. So, the above equation becomes:

\frac{P_{1} }{P_{2} } =\frac{m_{1} }{m_{2} }    ...(1)

The relation to determine electrical power for both heaters A and B are:

P_{1}=\frac{V^{2} }{R_{1} }     and

P_{2}=\frac{V^{2} }{R_{2} }

Here V is the voltage applied to both the heaters and is equal.

So, the ratio of electrical power of heaters is:

\frac{P_{1} }{P_{2} } =\frac{R_{2} }{R_{1} }     ....(2)

But according to the problem, the electrical power is converted into the thermal power. So,equation (1) and (2) are equal. Hence,

\frac{m_{1} }{m_{2} } =\frac{R_{2} }{R_{1} }

Substitute the suitable values in the above equation.

\frac{1 }{5.80 } =\frac{R_{2} }{R_{1} }

\frac{R_{1} }{R_{2} }=5.80

6 0
3 years ago
The table below shows 4 examples of pairs of objects, their masses, and the distance between them. In which example is the gravi
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Answer:

example two

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They have the greatest masses and close proximety relative to the rest, (If you have two black holes each with a solar mass only 1 mile away from one another, they will be highly atracted and probly

orbit each other once a second or so. But now lets try to put the earth and moon one half mile away from each other, they orbit each other much much slower then the two black holes, its becuase the gigantic mass of the black holes overwalms the closser distance between earth and the moon

Have a great day,

enjoy life.

3 0
3 years ago
What rock type does the principle of superposition apply to and how is the principle of superposition used to study the history
Effectus [21]
New rock get on top of old rock to form new layers of rock
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4 years ago
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