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Kitty [74]
3 years ago
5

Prove that, s=u+v/2please I need help ​

Physics
1 answer:
Hoochie [10]3 years ago
5 0

Answer:

Actually the formulae is S=(u+v/2)t

.TO explain,from average velocity=distance /time

and average velocity is u+v/2

hence using the formular

Average velocity=distance/time

distance will be=average velocity ×time

so S=(u+v/2)t

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How fast does a 2 MeV fission neutron travel through a reactor core?
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Answer:

The answer is 1.956 \times 10^7\ m/s

Explanation:

The amount of energy is not enough to apply the relativistic formula of energy E = mc^2, so the definition of energy in this case is

E = \frac{1}{2}m v^2.

From the last equation,

v= \sqrt{2E/m}

where

E = 2 MeV = 3.204 \times 10^{-13} J

and the mass of the neutron is

m = 1.675\times 10^{-27}\ Kg.

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v = 1.956 \times 10^7\ m/s

the equivalent of 0.065 the speed of light.

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3 years ago
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The initial momentum of the yellow and the orange train is 1000kgm/s.

Momentum is the product of the mass and velocity of any object.

Momentum is denoted by P.

Momentum P = mv , where m = mass and v = velocity.

<h3>Given:</h3>

Mass of the orange train = 200kg

Velocity of the orange train = 1m/s

So, the momentum of the orange train will be,

                            ∴    P = mv

                                  P = 200 x 1

                                  P = 200 kgm/s

∴   The initial momentum of the orange train is 200kgm/s.

Mass of the yellow train = 100kg

Velocity of the yellow train = 8m/s

So, the momentum of the yellow train will be,

                            ∴    P = mv

                                  P = 100 x 8

                                  P = 800 kgm/s

∴ The initial momentum of the yellow train is 800kgm/s.

Therefore, the initial momentum of the yellow and the orange train is 1000kgm/s.

Learn more about momentum here:

brainly.com/question/25849204

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5 0
2 years ago
A positive charge of 8.0 × 10-4 C is in an electric field that exerts a force of 3.5 × 10-4 N on it. What is the strength of the
Gennadij [26K]

Answer:

E = 0.437 N/C

Explanation:

Given that,

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Electric force, F=3.5\times 10^{-4}\ N

Let the strength of the electric field is E. We know that, the electric force is given by :

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Where

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E=\dfrac{F}{q}\\\\E=\dfrac{3.5\times 10^{-4}}{8\times 10^{-4}}\\E=0.437\ N/C

So, the strength of the electric field is equal to 0.437 N/C.

6 0
3 years ago
A loop of wire is placed in a uniform magnetic field. (a) For what orientation of the loop is the magnetic flux a maximum? The p
ra1l [238]

Answer:

1) The plane of the loop is perpendicular to the magnetic field.

2) The magnetic flux is independent of the orientation of the loop.p

Explanation:

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5 0
3 years ago
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