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Oksanka [162]
2 years ago
14

Which of the following is the most important factor in determining an element’s place in the periodic table?

Physics
2 answers:
Ivanshal [37]2 years ago
7 0
It’s A Bc I took the test
umka21 [38]2 years ago
5 0
A give brainliest answer plz
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3. what could you do to increase the precision of your measurements? What factors limit the
Vika [28.1K]

Answer:

Use specific tools built specifically for that specific measurement.

Explanation:

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3 years ago
In a cell protein synthesis is the primary function of
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In a cell, protein synthesis  is the primary function of the ribosomes, found in both eukaryotic and prokaryotic cells.

A Ribosome is a cell organelle that makes protein. The location of the ribosome  in a cell determine the kind of protein it makes.  If the ribosome is attached to the endoplasmic reticulum, the proteins made are utilized both  within and outside the cell. If the ribosome is in the cytoplasm, floating freely, then the kind of protein made will be utilized within the cell only.



8 0
3 years ago
A 3.15-kg object is moving in a plane, with its x and y coordinates given by x = 6t2 − 4 and y = 5t3 + 6, where x and y are in m
ArbitrLikvidat [17]

Answer:

<h2>206.67N</h2>

Explanation:

The sum of force along both components x and y is expressed as;

\sum Fx = ma_x  \ and \ \sum Fy = ma_y

The magnitude of the net force which is also known as the resultant will be expressed as R =\sqrt{(\sum Fx)^2 + (\sum Fx )^2}

To get the resultant, we need to get the sum of the forces along each components. But first lets get the acceleration along the components first.

Given the position of the object along the x-component to be x = 6t² − 4;

a_x = \frac{d^2 x }{dt^2}

a_x = \frac{d}{dt}(\frac{dx}{dt} )\\ \\a_x = \frac{d}{dt}(6t^{2}-4  )\\\\a_x = \frac{d}{dt}(12t  )\\\\a_x = 12m/s^{2}

Similarly,

a_y = \frac{d}{dt}(\frac{dy}{dt} )\\ \\a_y = \frac{d}{dt}(5t^{3} +6 )\\\\a_y = \frac{d}{dt}(15t^{2}   )\\\\a_y = 30t\\a_y \ at \ t= 2.15s; a_y = 30(2.15)\\a_y = 64.5m/s^2

\sum F_x = 3.15 * 12 = 37.8N\\\sum F_y = 3.15 * 64.5 = 203.18N

R = \sqrt{37.8^2+203.18^2}\\ \\R = \sqrt{1428.84+41,282.11}\\ \\R = \sqrt{42.710.95}\\ \\R = 206.67N

Hence, the magnitude of the net force acting on this object at t = 2.15 s is approximately 206.67N

7 0
3 years ago
A bus that was moving at a high speed stopped suddenly. One of
fiasKO [112]

Answer:

this doesn't make sinces

7 0
2 years ago
Q1.
Vesnalui [34]

Answer:

P = 450 J

Explanation:

Given that,

Mass of a child, m = 18 kg

The vertical distance from the top to the bottom of the slide is 2.5 metres.

The Gravitational field strength = 10 N/kg

We need to find the decrease in gravitational potential energy of the child sliding from the  top to the bottom of the slide.

The formula for the gravitational potential energy is given by :

P = mgh

Substituting all the values,

P = 18 kg × 10 m/s² × 2.5 m

P = 450 J

Hence, the decrease in gravitational potential energy is 450 J.

4 0
2 years ago
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