there are 6 moles of oxygen in Zn(No3)2
The balanced chemical reaction is written as:
<span>3NO2 + H2O = 2HNO3 + NO
Assuming that the gases in this reaction are ideal gas, then we can use the conversion from L to moles which is 1 mol of ideal gas is equal to 22.4 L. We calculate as follows:
538 L NO2 ( 1 mol / 22.4L ) ( 1 mol NO / 3 mol NO2 ) ( 22.4 L / 1 mol ) = 179.33 L NO is produced</span>
Answer:
Option B
Explanation:
Salt is a non-volatile solute and hence adding salt will increase the boiling point of water and hence reduce the vapor pressure. While on the other hand, adding more water will require more time to boil and hence produce vapor and thus the vapor pressure. Shaking will also not help in increasing the vapor pressure. Thus, only increasing the temperature of the water will create more vapors at a faster rate and hence increase the vapor pressure.
Thus, option B is the correct answer
Answer:
we will use the Clausius-Clapeyron equation to estimate the vapour pressures of the boiling ethanol at sea level pressure of 760mmHg:
ln (P2/P1) = ![\frac{ΔvapH}{R}([tex]\frac{1}{T1}](https://tex.z-dn.net/?f=%5Cfrac%7B%CE%94vapH%7D%7BR%7D%28%5Btex%5D%5Cfrac%7B1%7D%7BT1%7D)
-
)
where
P1 and P2 are the vapour pressures at temperatures T1 and T2
Δ
vapH = the enthalpy of vaporization of the ETHANOL
R = the Universal Gas Constant
In this problem,
P
1
=
100 mmHg
; T
1
=
34.7 °C
=
307.07 K
P
2
=
760mmHg
T
2
=T⁻²=?
Δ
vap
H
=
38.6 kJ/mol
R
=
0.008314 kJ⋅K
-1
mol
-1
ln
(
760/10)=(0.00325 - T⁻²) (38.6kJ⋅mol-1
/0.008314
)
0.0004368=(0.00325 - T⁻²)
T⁻²=0.002813
T² = 355.47K
Mg 10
fe 24
s 18
i 54
divide by smallest no.
mg1
fe 2.4/2
s 1.8/2
i 5.4/5
if u think this is wrong comment i will fix it
Thanks!
