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2 years ago

The sum of 4.824 + 2.03 + 4.72319 + 123.4567 + 111.1 expressed to the

Chemistry

1 answer:

Olin [163]2 years ago

4 0

Answer:

246.13389

Explanation:

Simplify the expression.

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- Write down Rutherford's atomic model with diagram .also write down defects of Rutherford's atomic model. - write down neil boh

anastassius [24]

this is the answer

sorry if the answer is wrong

5 0

3 years ago

Calculate the density of sulfuric acid from the information that 35.4 mL of the acid masses 65.14 g.

vladimir1956 [14]

Answer:

<h3>The answer is 1.84 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{65.14}{35.4} \\ = 1.840112994...$

We have the final answer as

Hope this helps you

3 0

2 years ago

What is the new concentration of 25.0mL added to 125.0mL of 0.150M

____ [38]

Answer:

The new concentration is 0.125 M.

Explanation:

Given data:

Initial volume V₁ = 125.0 mL

Initial molarity M₁ = 0.150 M

New volume V₂ = 25 mL +125 mL = 150 mL

New concentration M₂ = ?

Solution:

M₁V₁ = M₂V₂

0.150 M × 125 mL = M₂ × 150 mL

M₂ = 0.150 M × 125 mL / 150mL

M₂ = 18.75 M.mL/150 mL

M₂ = 0.125 M

The new concentration is 0.125 M.

8 0

3 years ago

Convert 135 Meters to kilometers

tamaranim1 [39]

Answer:

0.135 km

Explanation:

1 km = 1000 meters

7 0

2 years ago

Which substance has Hf defined as 0 kJ/mol? H2O (s) Ne (l) O2 (g) CO2 (g)

vlabodo [156]

Answer:

O₂ (g).

Explanation:

All elements that found in nature has heat of formation (Hf) equal 0 J/mol.

So, the substance that has heat of formation (Hf) equal 0 J/mol is O₂ (g).

H₂O is formed from the reaction of hydrogen and oxygen and has Hf, Also, the solidification of H₂O (s) from H₂O (l) has (Hf).

Although, Ne (g) is found in nature and has no Hf, the liquification to form Ne (l) has heat of formation (Hf).

CO₂ (g) is formed from the reaction between carbon and oxygen and so has heat of formation (Hf).

8 0

3 years ago

Read 2 more answers