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ivann1987 [24]
2 years ago
12

II. Resuelve los siguientes ejercicios (consulta La tabla entalpias estándar de formación, que se encuentra en el apartado de do

cumentos digitales)
1. Calcula la entalpia de reacción del siguiente proceso y menciona si es una reacción endotérmica o exotérmica.
2NO(g) + O 2(g) → 2NO 2 (g)
Chemistry
1 answer:
Afina-wow [57]2 years ago
4 0

For all the people that don't speak this language This is what it says.

Solve the following exercises (see The standard formation enthalpies table, found in the digital documents section)

1. Calculate the enthalpy of the reaction for the following process and state whether it is an endothermic or exothermic reaction

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What type of elements make up an ionic compound
xenn [34]

Answer:

Those that “prefer” A charge; the Halogens and Chalcogens are good examples - Halogen MEANS salt forming, and even organic compounds can form salts; look up “tropylium ion”.

Explanation:

5 0
3 years ago
A balloon is filled with 0.75 L of Helium gas at 35 °C. If the temperature is increased to 113 °C, what thewill new volume be?
faust18 [17]

Answer: 0.9398 Liters

Explanation:

Charles' Law

V1/ T1 = V2/T2

0.75/35 = ?/113

0.75/35 = 0.9398/113

4 0
3 years ago
What is the conjugate acid in the following equation:
yanalaym [24]

Answer:

HNO₂

Explanation:

An acid is a proton donor; a base is a proton acceptor.

Thus, NO₂⁻ is the base, because it accepts a proton from the water.

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The conjugate base is what's left after the acid has given up its proton.

The conjugate acid is what's formed when the base has accepted a proton.

NO₂⁻/HNO₂ make one conjugate acid/base pair, and H₂O/OH⁻ are the other conjugate acid/base pair.

NO₂⁻ + H₂O ⇌ HNO₂ + OH⁻

base     acid     conj.      conj.

                        acid       base

5 0
3 years ago
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The wick and the wax

Sorry if that was useless, I'm not sure how generalized you were being

6 0
3 years ago
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Match these items.
mars1129 [50]
Here are the possible answers for the following questions above:
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6 0
3 years ago
Read 2 more answers
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